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prove that the paired degree cannot be equal to 8k+38k+3

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Q. prove that the paired degree cannot be equal to 8k+38k+3
  1. Assume Degree of Polynomial: Let's assume that the degree of a polynomial can be equal to 8k+38k+3 for some integer kk.
  2. Degree is Whole Number: Now, the degree of a polynomial is always a whole number since it's the highest power of the variable in the polynomial.
  3. Term with Highest Power: If we have a polynomial with a degree of 8k+38k+3, it means that there is a term in the polynomial with the variable raised to the power of 8k+38k+3.
  4. Degree Calculation in Standard Form: The degree of a polynomial is the sum of the exponents of the variables in a term when the term is in its standard form. For example, the degree of 2x2y32x^2y^3 is 2+3=52+3=5.
  5. Paired Degree Explanation: However, when we talk about "paired degree," we're referring to the sum of the degrees of two polynomials when multiplied together. If we have two polynomials of degrees mm and nn, the degree of their product is m+nm+n.
  6. Addition of Degrees: If we multiply two polynomials with degrees that are multiples of 88, their degrees would add up to a number that is also a multiple of 88, since 8m+8n=8(m+n)8m + 8n = 8(m+n).
  7. Odd and Even Numbers: Adding 33 to a multiple of 88 will never result in another multiple of 88, because 88 is an even number and 33 is odd, so 8k+38k + 3 will always be odd, while 8(m+n)8(m+n) is always even.
  8. Implication of Degree: Therefore, the degree of the product of two polynomials (paired degree) cannot be of the form 8k+38k+3, because it would imply that an even number (8k8k) plus an odd number (33) is equal to another even number, which is not possible.

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