Q. prove that the paired degree cannot be equal to 8k+3
Assume Degree of Polynomial: Let's assume that the degree of a polynomial can be equal to 8k+3 for some integer k.
Degree is Whole Number: Now, the degree of a polynomial is always a whole number since it's the highest power of the variable in the polynomial.
Term with Highest Power: If we have a polynomial with a degree of 8k+3, it means that there is a term in the polynomial with the variable raised to the power of 8k+3.
Degree Calculation in Standard Form: The degree of a polynomial is the sum of the exponents of the variables in a term when the term is in its standard form. For example, the degree of 2x2y3 is 2+3=5.
Paired Degree Explanation: However, when we talk about "paired degree," we're referring to the sum of the degrees of two polynomials when multiplied together. If we have two polynomials of degrees m and n, the degree of their product is m+n.
Addition of Degrees: If we multiply two polynomials with degrees that are multiples of 8, their degrees would add up to a number that is also a multiple of 8, since 8m+8n=8(m+n).
Odd and Even Numbers: Adding 3 to a multiple of 8 will never result in another multiple of 8, because 8 is an even number and 3 is odd, so 8k+3 will always be odd, while 8(m+n) is always even.
Implication of Degree: Therefore, the degree of the product of two polynomials (paired degree) cannot be of the form 8k+3, because it would imply that an even number (8k) plus an odd number (3) is equal to another even number, which is not possible.