Q. Prove step by step that (secsecx)÷(tantanx)−(tantanx)÷(1+secsecx) gives: cotcotx
Rewrite secsecx: Rewrite secsecx as cos(cosx)1 and tantanx as cos(cosx)sin(sinx).cos(cosx)1÷cos(cosx)sin(sinx)−cos(cosx)sin(sinx)÷(1+cos(cosx)1)
Simplify division: Simplify the division by multiplying by the reciprocal.(cos(cosx)1)×(sin(sinx)cos(cosx))−(cos(cosx)sin(sinx))×(1+cos(cosx)1cos(cosx))
Simplify expressions: Simplify the expressions. sin(sinx)cos(cosx) - cos(cosx)+1sin(sinx)cos(cosx)
Combine terms: Combine the terms over a common denominator.(sin(sinx)cos(cosx))×(cos(cosx)+1cos(cosx)+1)−(cos(cosx)+1sin(sinx)cos(cosx))
Simplify numerator: Simplify the numerator. cos(cosx)+1cos2(cosx)+cos(cosx)−sin(sinx)cos(cosx)
Factor out cos: Factor out cos(cosx) in the numerator.cos(cosx)+1cos(cosx)(cos(cosx)+1−sin(sinx))
Cancel terms: Cancel out the cos(cosx)+1 terms in the numerator and denominator.sin(sinx)cos(cosx)
Rewrite as cot: Rewrite sin(sinx)cos(cosx) as cot(cotx).cot(cotx)
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