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prove (sinx+cosx)2=1+sin2x(\sin x+\cos x)^2=1+\sin 2x

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Q. prove (sinx+cosx)2=1+sin2x(\sin x+\cos x)^2=1+\sin 2x
  1. Expand Identity: Expand the left side using the identity (a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2.\newline(sinx+cosx)2=sin2x+2sinxcosx+cos2x(\sin x + \cos x)^2 = \sin^2 x + 2\sin x \cos x + \cos^2 x
  2. Recognize Identity: Recognize that sin2x+cos2x=1\sin^2 x + \cos^2 x = 1.\newlinesin2x+cos2x=1\sin^2 x + \cos^2 x = 1
  3. Identify Double Angle Formula: Identify that 2sinxcosx2\sin x \cos x is the double angle formula for sin2x\sin 2x.\newline2sinxcosx=sin2x2\sin x \cos x = \sin 2x
  4. Substitute Identities: Substitute the identities into the expanded equation.\newline1+2sinxcosx=1+sin2x1 + 2\sin x \cos x = 1 + \sin 2x
  5. Check Equation: Check if the left side and the right side of the equation are the same.\newline1+sin2x=1+sin2x1 + \sin 2x = 1 + \sin 2x