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Point 
N is located at -9 . Points 
O and 
P are each 7 units away from Point 
N. Where are 
O and 
P located?

O=

P=

Point N \mathrm{N} is located at 9-9 . Points O \mathrm{O} and P \mathrm{P} are each 77 units away from Point N \mathrm{N} . Where are O \mathrm{O} and P \mathrm{P} located?\newlineO=P= \mathrm{O}=\square \quad \mathrm{P}= \square

Full solution

Q. Point N \mathrm{N} is located at 9-9 . Points O \mathrm{O} and P \mathrm{P} are each 77 units away from Point N \mathrm{N} . Where are O \mathrm{O} and P \mathrm{P} located?\newlineO=P= \mathrm{O}=\square \quad \mathrm{P}= \square
  1. Given Data: Given that Point NN is located at 9-9 on a number line, and Points OO and PP are each 77 units away from Point NN, we need to find two points that are 77 units away from 9-9. One will be to the left (a negative direction) and one will be to the right (a positive direction) on the number line.
  2. Find Point O: To find Point O, which is 77 units to the left of Point N, we subtract 77 from the position of Point N.\newlineCalculation: 97=16-9 - 7 = -16\newlinePoint O is located at 16-16.
  3. Find Point P: To find Point P, which is 77 units to the right of Point N, we add 77 to the position of Point N.\newlineCalculation: 9+7=2-9 + 7 = -2\newlinePoint P is located at 2-2.

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