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Petermine all solutions for 
0 <= t <= 4

2pi cos(pi t)+2pi cos(2pi t)=0

Petermine all solutions for 0t4 0 \leqslant t \leqslant 4 \newline2πcos(πt)+2πcos(2πt)=0 2 \pi \cos (\pi t)+2 \pi \cos (2 \pi t)=0

Full solution

Q. Petermine all solutions for 0t4 0 \leqslant t \leqslant 4 \newline2πcos(πt)+2πcos(2πt)=0 2 \pi \cos (\pi t)+2 \pi \cos (2 \pi t)=0
  1. Isolate Cosine Term: Isolate one of the cosine terms.\newline2πcos(πt)+2πcos(2πt)=02\pi \cos(\pi t) + 2\pi \cos(2\pi t) = 0\newline2πcos(πt)=2πcos(2πt)2\pi \cos(\pi t) = -2\pi \cos(2\pi t)\newlineDivide both sides by 2π2\pi.\newlinecos(πt)=cos(2πt)\cos(\pi t) = -\cos(2\pi t)
  2. Apply Double Angle Identity: Use the double angle identity for cosine.\newlinecos(πt)=cos(2πt)\cos(\pi t) = -\cos(2\pi t)\newlinecos(πt)=1+2sin2(πt)\cos(\pi t) = -1 + 2\sin^2(\pi t)

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