Perimeter, Ares, and VolumeIdentilying side lengths that give right trianglesDetermine whether a triangle with the given side lengths is a right triangle.\begin{tabular}{|l|c|c|c|}\hline \multicolumn{1}{|c|}{ Side lengths } & Right triangle & \begin{tabular}{c} Not a right \\triangle\end{tabular} & \begin{tabular}{c} Not enough \\information\end{tabular} \\\hline (a) 7,24,25 & 0 & 0 & 0 \\\hline (b) 4,7,8 & 0 & 0 & 0 \\\hline (c) 10,24,26 & 0 & 0 & 0 \\\hline (d) 22,29,36 & 0 & 0 & 0 \\\hline\end{tabular}
Q. Perimeter, Ares, and VolumeIdentilying side lengths that give right trianglesDetermine whether a triangle with the given side lengths is a right triangle.\begin{tabular}{|l|c|c|c|}\hline \multicolumn{1}{|c|}{ Side lengths } & Right triangle & \begin{tabular}{c} Not a right \\triangle\end{tabular} & \begin{tabular}{c} Not enough \\information\end{tabular} \\\hline (a) 7,24,25 & 0 & 0 & 0 \\\hline (b) 4,7,8 & 0 & 0 & 0 \\\hline (c) 10,24,26 & 0 & 0 & 0 \\\hline (d) 22,29,36 & 0 & 0 & 0 \\\hline\end{tabular}
Apply Pythagorean Theorem: To determine if a set of three side lengths forms a right triangle, we can use the Pythagorean theorem, which states that for a right triangle with legs a and b, and hypotenuse c, the following equation holds true: a2+b2=c2. We will apply this theorem to each set of side lengths.
Check Set (a): For set (a) with side lengths 7, 24, and 25, we assume the longest side is the hypotenuse, so we check if 72+242=252.Calculating each term gives us 49+576=625.Adding the squares of the shorter sides, we get 49+576=625, which is equal to 252.Therefore, the set (a) does form a right triangle.
Check Set (b): For set (b) with side lengths 4, 7, and 8, we check if 42+72=82.Calculating each term gives us 16+49=64.Adding the squares of the shorter sides, we get 16+49=65, which is not equal to 82=64.Therefore, the set (b) does not form a right triangle.
Check Set (c): For set (c) with side lengths 10, 24, and 26, we check if 102+242=262.Calculating each term gives us 100+576=676.Adding the squares of the shorter sides, we get 100+576=676, which is equal to 262.Therefore, the set (c) does form a right triangle.
Check Set (d): For set (d) with side lengths 22, 29, and 36, we check if 222+292=362.Calculating each term gives us 484+841=1325.Adding the squares of the shorter sides, we get 484+841=1325, which is not equal to 362=1296.Therefore, the set (d) does not form a right triangle.