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Perform the division. (18x^(16)-4x^(14)+12x^(12)-16x^(10))÷(2x^(18))

Perform the division.\newline(18x16−4x14+12x12−16x10)÷(2x18) \left(18 x^{16}-4 x^{14}+12 x^{12}-16 x^{10}\right) \div\left(2 x^{18}\right)

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Full solution

Q. Perform the division.\newline(18x16−4x14+12x12−16x10)÷(2x18) \left(18 x^{16}-4 x^{14}+12 x^{12}-16 x^{10}\right) \div\left(2 x^{18}\right)
  1. Divide by 2x182x^{18}: First, let's divide each term of the polynomial by 2x182x^{18}.
  2. Divide first term: Divide the first term: (18x16)/(2x18)=9x−2(18x^{16})/(2x^{18}) = 9x^{-2}.
  3. Divide second term: Divide the second term: (−4x14)/(2x18)=−2x−4(-4x^{14})/(2x^{18}) = -2x^{-4}.
  4. Divide third term: Divide the third term: (12x12)/(2x18)=6x−6(12x^{12})/(2x^{18}) = 6x^{-6}.
  5. Divide fourth term: Divide the fourth term: (−16x10)/(2x18)=−8x−8(-16x^{10})/(2x^{18}) = -8x^{-8}.
  6. Combine all terms: Now, let's put all the terms together to get the final answer.

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