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Pedro deposits 
$880 every month into an account earning a monthly interest rate of 
0.675%. How much would he have in the account after 6 months, to the nearest dollar? Use the following formula to determine your answer.

A=d(((1+i)^(n)-1)/(i))

A= the future value of the account after 
n periods

d= the amount invested at the end of each period

i= the interest rate per period

n= the number of periods
Answer:

Pedro deposits $880 \$ 880 every month into an account earning a monthly interest rate of 0.675% 0.675 \% . How much would he have in the account after 66 months, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:

Full solution

Q. Pedro deposits $880 \$ 880 every month into an account earning a monthly interest rate of 0.675% 0.675 \% . How much would he have in the account after 66 months, to the nearest dollar? Use the following formula to determine your answer.\newlineA=d((1+i)n1i) A=d\left(\frac{(1+i)^{n}-1}{i}\right) \newlineA= A= the future value of the account after n n periods\newlined= d= the amount invested at the end of each period\newlinei= i= the interest rate per period\newlinen= n= the number of periods\newlineAnswer:
  1. Identify Given Values: Identify the given values from the problem.\newlineWe are given:\newlinedd (the amount invested at the end of each period) = $880\$880\newlineii (the interest rate per period) = 0.675%0.675\% or 0.006750.00675 in decimal form\newlinenn (the number of periods) = 66 months\newlineWe will use these values in the formula A=d((1+i)n1i)A=d\left(\frac{(1+i)^{n}-1}{i}\right) to find AA, the future value of the account after nn periods.
  2. Convert Interest Rate: Convert the interest rate from a percentage to a decimal. 0.675%0.675\% as a decimal is 0.675/100=0.006750.675 / 100 = 0.00675.
  3. Substitute Values: Substitute the values into the formula.\newlineA=880×((1+0.00675)61)/0.00675A = 880 \times \left(\left(1 + 0.00675\right)^{6} - 1\right) / 0.00675
  4. Calculate Inside Parentheses: Calculate the value inside the parentheses.\newlineCalculate (1+0.00675)6(1 + 0.00675)^{6} first.\newline(1+0.00675)61.040911(1 + 0.00675)^{6} \approx 1.040911
  5. Subtract Result: Subtract 11 from the result obtained in Step 44.\newline1.0409111=0.0409111.040911 - 1 = 0.040911
  6. Divide by Interest Rate: Divide the result from Step 55 by the interest rate.\newline0.040911/0.006756.0594070.040911 / 0.00675 \approx 6.059407
  7. Multiply by Amount: Multiply the result from Step 66 by the amount invested per period.\newline880×6.0594075332.23816880 \times 6.059407 \approx 5332.23816
  8. Round to Nearest Dollar: Round the result to the nearest dollar.\newlineThe future value of the account after 66 months, rounded to the nearest dollar, is approximately $5332\$5332.

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