Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Paradigm
Specialising in O Level Mathematic
In the diagram, 
ABC is a triangle where 
M is the midpoint of 
AC.
The point 
P lies on the line 
BM such that 
BP=(1)/(3)BM.
The point 
Q lies on the line 
BC such that 
BQ:QC=1:4.
Given that 
vec(AB)=b and 
vec(AC)=c.
(a) Express, as simply as possible, in terms of 
b and or 
c,
(i) 
vec(BC),

Paradigm\newlineSpecialising in O Level Mathematic\newlineIn the diagram, ABC A B C is a triangle where M M is the midpoint of AC A C .\newlineThe point P P lies on the line BM B M such that BP=13BM B P=\frac{1}{3} B M .\newlineThe point Q Q lies on the line BC B C such that BQ:QC=1:4 B Q: Q C=1: 4 .\newlineGiven that ABundefined=b \overrightarrow{A B}=b and M M 00.\newline(a) Express, as simply as possible, in terms of M M 11 and or M M 22,\newline(i) M M 33,

Full solution

Q. Paradigm\newlineSpecialising in O Level Mathematic\newlineIn the diagram, ABC A B C is a triangle where M M is the midpoint of AC A C .\newlineThe point P P lies on the line BM B M such that BP=13BM B P=\frac{1}{3} B M .\newlineThe point Q Q lies on the line BC B C such that BQ:QC=1:4 B Q: Q C=1: 4 .\newlineGiven that ABundefined=b \overrightarrow{A B}=b and M M 00.\newline(a) Express, as simply as possible, in terms of M M 11 and or M M 22,\newline(i) M M 33,
  1. Calculate Vector AM: Since M is the midpoint of AC, vector AM is half of vector AC.\newlineCalculation: AM=12AC\vec{AM} = \frac{1}{2} \vec{AC}
  2. Calculate Vector BM: Vector BM is the sum of vectors BA and AM.\newlineCalculation: BM=BA+AM\vec{BM} = \vec{BA} + \vec{AM}
  3. Determine Vector BA: Since vector BA is the opposite of vector AB, we can write it as b-\mathbf{b}.\newlineCalculation: BA=AB=b\vec{BA} = -\vec{AB} = -\mathbf{b}
  4. Substitute into BM equation: Substitute AM\vec{AM} and BA\vec{BA} into the equation for BM\vec{BM}.\newlineCalculation: BM=b+12c\vec{BM} = -b + \frac{1}{2} c
  5. Calculate Vector BC: Vector BC is the sum of vectors BM and MC.\newlineCalculation: BC=BM+MC\vec{BC} = \vec{BM} + \vec{MC}
  6. Calculate Vector MC: Since MM is the midpoint of ACAC, vector MC\textbf{MC} is also half of vector AC\textbf{AC} but in the opposite direction.\newlineCalculation: MC=12AC\vec{MC} = -\frac{1}{2} \vec{AC}
  7. Substitute into BC equation: Substitute MC\vec{MC} and BM\vec{BM} into the equation for BC\vec{BC}.\newlineCalculation: BC=(b+12c)+(12c)\vec{BC} = (-b + \frac{1}{2} c) + (-\frac{1}{2} c)
  8. Simplify BC equation: Simplify the equation for BC\vec{BC}.\newlineCalculation: BC=b+12c12c\vec{BC} = -b + \frac{1}{2} c - \frac{1}{2} c
  9. Cancel out terms: Realize that the cc terms cancel each other out.\newlineCalculation: BC=b\vec{BC} = -b

More problems from Write inverse variation equations