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p(x)=(x-0.95)(500-100 x)
The equation models
p, the daily profit, in dollars, a food truck makes by selling their signature tacos at a price of
x dollars each. What is the daily profit if the tacos are sold at
$3 each?
Choose 1 answer:
(A)
$410
(B)
$600
(C)
$820
(D)
$2,460

$p(x)=(x-0.95)(500-100 x)$ $\newline$ The equation models $p$ , the daily profit, in dollars, a food truck makes by selling their signature tacos at a price of $x$ dollars each. What is the daily profit if the tacos are sold at $\$ 3$ each? $\newline$ Choose $1$ answer: $\newline$ (A) $\$ 410$ $\newline$ (B) $\$ 600$ $\newline$ (C) $\$ 820$ $\newline$ (D) $\$ 2,460$

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Write linear functions: word problems

Full solution

Q.

p(x)=(x-0.95)(500-100 x)

\newline

The equation models

p

, the daily profit, in dollars, a food truck makes by selling their signature tacos at a price of

x

dollars each. What is the daily profit if the tacos are sold at

\$ 3

each?

\newline

Choose

1

answer:

\newline

(A)

\$ 410

\newline

(B)

\$ 600

\newline

(C)

\$ 820

\newline

(D)

\$ 2,460

Substitute price per taco: Substitute the price per taco into the profit equation. $\newline$ We are given the profit equation $p(x) = (x - 0.95)(500 - 100x)$ and we need to find the profit when $x = \$3$ . $\newline$ Substitute $x$ with $3$ in the equation. $\newline$ $p(3) = (3 - 0.95)(500 - 100 \times 3)$
Perform calculations inside parentheses: Perform the calculations inside the parentheses. $\newline$ Calculate the first part of the equation $(3 - 0.95)$ and the second part $(500 - 100 \times 3)$ . $\newline$ First part: $3 - 0.95 = 2.05$ $\newline$ Second part: $500 - 300 = 200$ $\newline$ Now we have $p(3) = 2.05 \times 200$
Multiply results to find profit: Multiply the results to find the profit. $\newline$ Multiply $2.05$ by $200$ to get the profit. $\newline$ $p(3) = 2.05 \times 200 = 410$

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