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P(t)=1,800(1.004)tP(t) = 1,800(1.004)^t\newlineThe function models PP, the amount of money, in dollars, in Yara's savings account tt years after she opened the account with an initial deposit of $1,800\$1,800. How much money is in Yara's account 55 years after her initial deposit if she makes no deposits or withdraws in that time?\newlineChoose 11 answer:\newline(A) $1,836.29\$1,836.29\newline(B) $1,873.31\$1,873.31\newline(C) $2,189.98\$2,189.98\newline(D) $9,036\$9,036

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Q. P(t)=1,800(1.004)tP(t) = 1,800(1.004)^t\newlineThe function models PP, the amount of money, in dollars, in Yara's savings account tt years after she opened the account with an initial deposit of $1,800\$1,800. How much money is in Yara's account 55 years after her initial deposit if she makes no deposits or withdraws in that time?\newlineChoose 11 answer:\newline(A) $1,836.29\$1,836.29\newline(B) $1,873.31\$1,873.31\newline(C) $2,189.98\$2,189.98\newline(D) $9,036\$9,036
  1. Given Function Calculation: Given the function P(t)=1,800(1.004)tP(t) = 1,800(1.004)^{t}, we need to calculate the amount of money in Yara's account after 55 years. We will substitute tt with 55 in the function to find P(5)P(5).
  2. Substitute tt with 55: Perform the calculation for P(5)P(5) using the given function:\newlineP(5)=1,800(1.004)(5)P(5) = 1,800(1.004)^{(5)}
  3. Evaluate Expression: Use a calculator or a computational tool to evaluate the expression: P(5)=1,800×(1.004)5P(5) = 1,800 \times (1.004)^5
  4. Multiply Result: After calculating the expression, we get: P(5)1,800×1.02020201P(5) \approx 1,800 \times 1.02020201
  5. Round to Two Decimal Places: Now, multiply 1,8001,800 by 1.020202011.02020201 to find the final amount:\newlineP(5)1,800×1.020202011,836.36362P(5) \approx 1,800 \times 1.02020201 \approx 1,836.36362
  6. Compare with Answer Choices: Round the result to two decimal places to match the answer choices: P(5)$1,836.36P(5) \approx \$1,836.36
  7. Compare with Answer Choices: Round the result to two decimal places to match the answer choices:\newlineP(5)$1,836.36P(5) \approx \$1,836.36Compare the result with the given answer choices:\newline(A) $1,836.29\$1,836.29\newline(B) $1,873.31\$1,873.31\newline(C) $2,189.98\$2,189.98\newline(D) $9,036\$9,036\newlineThe closest answer to our calculation is (A) $1,836.29\$1,836.29.

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