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one output
values over the change in 
x-values (rise/run)
touches the 
y-axis; the beginning value of a situation
when graphed; has a constant slope
tical Line Test". If a vertical line would touch more than one
ing inputs only df repeating inputs have different outputs, it is
(4) Which of the following relations does
NOT represent a function?
A. 
{(5,8),(10,2),(12,-2),(15,-5)}
B. 
y=(1)/(2)x+8
C. Multiplying each input by 10 to produce

one output\newlinevalues over the change in x x -values (rise/run)\newlinetouches the y y -axis; the beginning value of a situation\newlinewhen graphed; has a constant slope\newlinetical Line Test

Full solution

Q. one output\newlinevalues over the change in x x -values (rise/run)\newlinetouches the y y -axis; the beginning value of a situation\newlinewhen graphed; has a constant slope\newlinetical Line Test
  1. Define Function: A function is defined as a relation where each input has exactly one output. To determine if a relation is a function, we can use the "Vertical Line Test". If a vertical line intersects the graph of the relation at more than one point, then the relation is not a function.
  2. Vertical Line Test: For choice A, we have a set of ordered pairs. We need to check if any xx-value is repeated with different yy-values. The pairs are {(5,8),(10,2),(12,2),(15,5)}\{(5,8),(10,2),(12,-2),(15,-5)\}. No xx-value is repeated, so this relation is a function.
  3. Check Choice A: For choice B, the equation y=12x+8y=\frac{1}{2}x+8 represents a straight line, which means for every xx-value there is only one yy-value. This is a function.
  4. Check Choice B: For choice C, the description is incomplete and does not provide enough information to determine if it's a function. However, the prompt asks for the relation that does NOT represent a function, so we can't conclude anything from this incomplete information. We need to look for an option that clearly does not represent a function.
  5. Incomplete Description: Since choices AA and BB are functions and choice CC is incomplete, we can't identify a relation that does NOT represent a function based on the given information. There seems to be a mistake in the problem statement as it does not provide a complete set of choices.

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