Resourcesdown chevron
Testimonials
Plans
Sign in
Sign up
Resourcesright arrow
Testimonials
Plans
Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

One of the legs of a right triangle measures 8cm and its hypotenuse measures 17cm. Find the measure of the other leg. If necessary, round to the nearest tenth. Answer: cm

One of the legs of a right triangle measures 8 cm 8 \mathrm{~cm} and its hypotenuse measures 17 cm 17 \mathrm{~cm} . Find the measure of the other leg. If necessary, round to the nearest tenth.\newlineAnswer: □\square cm \mathrm{cm}

View step-by-step helpView step-by-step help
Homeright chevron icon
Math Problemsright chevron icon
Algebra 2right chevron icon
Pythagorean Theorem and its converseright chevron icon

Full solution

Q. One of the legs of a right triangle measures 8 cm 8 \mathrm{~cm} and its hypotenuse measures 17 cm 17 \mathrm{~cm} . Find the measure of the other leg. If necessary, round to the nearest tenth.\newlineAnswer: □\square cm \mathrm{cm}
  1. Identify Known Sides: Identify the known sides of the right triangle and the unknown side we need to find.\newlineWe know one leg aa is 88 cm, and the hypotenuse cc is 1717 cm. We need to find the other leg bb.
  2. Use Pythagorean Theorem: Use the Pythagorean Theorem to set up the equation to find the unknown leg.\newlineThe Pythagorean Theorem states that in a right triangle, the square of the hypotenuse cc is equal to the sum of the squares of the other two sides aa and bb.\newlineSo, the equation is a2+b2=c2a^2 + b^2 = c^2.
  3. Plug in Values: Plug in the known values into the Pythagorean Theorem and solve for bb. We have a=8a = 8 cm and c=17c = 17 cm. Plugging these into the equation gives us: 82+b2=1728^2 + b^2 = 17^2.
  4. Calculate Squares: Calculate the squares of the known sides.\newline82=648^2 = 64 and 172=28917^2 = 289.\newlineSo, the equation becomes 64+b2=28964 + b^2 = 289.
  5. Subtract and Isolate: Subtract 6464 from both sides of the equation to isolate b2b^2.\newlineb2=289−64.b^2 = 289 - 64.\newlineb2=225.b^2 = 225.
  6. Take Square Root: Take the square root of both sides to solve for bb.b=225b = \sqrt{225}.b=15b = 15.

More problems from Pythagorean Theorem and its converse

Question
Find all solutions with 0∘≤θ≤180∘0^\circ \leq \theta \leq 180^\circ. Give the exact answer(s) in simplest form. If there are multiple answers, separate them with commas.\newlinecos⁡(θ)=−1\cos(\theta) = -1\newline‾∘\underline{\hspace{2em}}^\circ
Get tutor helpright-arrow

Posted 2 months ago

Question
Kimi's school is 1515 kilometers west of her house and 88 kilometers south of her friend Franklin's house. Every day, Kimi bicycles from her house to her school. After school, she bicycles from her school to Franklin's house. Before dinner, she bicycles home on a bike path that goes straight from Franklin's house to her own house. How far does Kimi bicycle each day?\newline_____\_\_\_\_\_ kilometers
Get tutor helpright-arrow

Posted 2 months ago

Question
Evaluate. Write your answer as an integer or as a decimal rounded to the nearest hundredth.\newlinecos⁡35∘=\cos 35^\circ = __
Get tutor helpright-arrow

Posted 2 months ago

Question
Find all solutions with −90∘≤θ≤90∘-90^\circ \leq \theta \leq 90^\circ. Give the exact answer(s) in simplest form. If there are multiple answers, separate them with commas.\newlinecsc⁡(θ)=−1\csc(\theta) = -1\newline____ ∘\_\_\_\_\,^\circ
Get tutor helpright-arrow

Posted 2 months ago

Question
Evaluate. Write your answer in simplified, rationalized form. Do not round.\newlinecot⁡30∘=\cot 30^\circ = ______
Get tutor helpright-arrow

Posted 2 months ago

Question
The terminal side of an angle θ\theta in standard position intersects the unit circle at (8485,1385)(\frac{84}{85}, \frac{13}{85}). What is cos⁡(θ)\cos(\theta)?\newlineWrite your answer in simplified, rationalized form.\newline______
Get tutor helpright-arrow

Posted 2 months ago

Question
−90∘<θ<90∘-90^\circ < \theta < 90^\circ. Find the value of θ\theta in degrees.\newlinetan⁡(θ)=0\tan(\theta) = 0\newlineWrite your answer in simplified, rationalized form. Do not round.\newlineθ=\theta = ____∘^\circ\newline
Get tutor helpright-arrow

Posted 2 months ago

Question
Evaluate. Write your answer in simplified, rationalized form. Do not round.\newlinecsc⁡60∘=\csc 60^\circ = ______
Get tutor helpright-arrow

Posted 2 months ago

Question
θ\theta is an acute angle. Find the value of θ\theta in degrees.\newlinesec⁡(θ)=2\sec(\theta) = \sqrt{2}\newlineθ=\theta = ____°\degree
Get tutor helpright-arrow

Posted 2 months ago

Question
Evaluate. Write your answer in simplified, rationalized form. Do not round.\newlinecos⁡90∘=\cos 90^\circ = ____
Get tutor helpright-arrow

Posted 3 months ago

View all (130)