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On the first day of spring, an entire field of flowering trees blossoms. The population of locusts consuming these flowers rapidly increases as the trees blossom.
The relationship between the elapsed time, 
t, in days, since the beginning of spring, and the total number of locusts, 
N_("day ")(t), is modeled by the following function:

N_("day ")(t)=300*(1.2)^(t)
Complete the following sentence about the weekly rate of change in the locust population.
Round your answer to two decimal places.
Every week, the number of locusts grows by a factor of

On the first day of spring, an entire field of flowering trees blossoms. The population of locusts consuming these flowers rapidly increases as the trees blossom.\newlineThe relationship between the elapsed time, t t , in days, since the beginning of spring, and the total number of locusts, Nday (t) N_{\text {day }}(t) , is modeled by the following function:\newlineNday (t)=300(1.2)t N_{\text {day }}(t)=300 \cdot(1.2)^{t} \newlineComplete the following sentence about the weekly rate of change in the locust population.\newlineRound your answer to two decimal places.\newlineEvery week, the number of locusts grows by a factor of

Full solution

Q. On the first day of spring, an entire field of flowering trees blossoms. The population of locusts consuming these flowers rapidly increases as the trees blossom.\newlineThe relationship between the elapsed time, t t , in days, since the beginning of spring, and the total number of locusts, Nday (t) N_{\text {day }}(t) , is modeled by the following function:\newlineNday (t)=300(1.2)t N_{\text {day }}(t)=300 \cdot(1.2)^{t} \newlineComplete the following sentence about the weekly rate of change in the locust population.\newlineRound your answer to two decimal places.\newlineEvery week, the number of locusts grows by a factor of
  1. Substitute tt with 77: To find the weekly rate of change, we need to calculate the factor by which the number of locusts grows in one week. Since one week is equivalent to 77 days, we will substitute tt with 77 in the given function Nday(t)=300×(1.2)tN_{\text{day}}(t) = 300 \times (1.2)^t.
  2. Calculate Nday(7)N_{\text{day}}(7): Now, let's calculate the value of Nday(7)N_{\text{day}}(7) to find out the number of locusts at the end of one week.\newlineNday(7)=300×(1.2)7N_{\text{day}}(7) = 300 \times (1.2)^{7}
  3. Calculate (1.2)7(1.2)^{7}: Perform the calculation for (1.2)7(1.2)^{7}. \newline(1.2)73.5832(1.2)^{7} \approx 3.5832
  4. Multiply by 300300: Now, multiply the result by 300300 to get the total number of locusts after one week.\newlineNday (7)=300×3.58321074.96N_{\text{day }}(7) = 300 \times 3.5832 \approx 1074.96
  5. Find factor of growth: However, we are interested in the factor of growth, not the actual number of locusts. The factor of growth is simply (1.2)7(1.2)^{7} since the initial population is multiplied by this factor after one week.
  6. Round to two decimal places: Round the factor of growth to two decimal places.\newlineThe weekly growth factor is approximately 3.583.58.

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