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On a camping trip, Whitney kept a log of the types of snakes she saw. She noted their colors and approximate lengths.\newlineThe probability that a snake is brown is 0.40.4, the probability that it is under 11 foot long is 0.90.9, and the probability that it is brown and under 11 foot long is 0.30.3.\newlineWhat is the probability that a randomly chosen snake is brown or under 11 foot long?\newlineWrite your answer as a whole number, decimal, or simplified fraction.

Full solution

Q. On a camping trip, Whitney kept a log of the types of snakes she saw. She noted their colors and approximate lengths.\newlineThe probability that a snake is brown is 0.40.4, the probability that it is under 11 foot long is 0.90.9, and the probability that it is brown and under 11 foot long is 0.30.3.\newlineWhat is the probability that a randomly chosen snake is brown or under 11 foot long?\newlineWrite your answer as a whole number, decimal, or simplified fraction.
  1. Define Events A and B: Let AA be the event that a snake is brown, and BB be the event that it's under 11 foot long. We know P(A)=0.4P(A) = 0.4, P(B)=0.9P(B) = 0.9, and P(A and B)=0.3P(A \text{ and } B) = 0.3.
  2. Calculate P(A or B)P(A \text{ or } B): We're looking for P(A or B)P(A \text{ or } B), which is P(A)+P(B)P(A and B)P(A) + P(B) - P(A \text{ and } B).
  3. Substitute Values: So, P(A or B)=0.4+0.90.3P(A \text{ or } B) = 0.4 + 0.9 - 0.3.
  4. Final Calculation: Doing the math, P(A or B)=1.0P(A \text{ or } B) = 1.0.

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