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$Of the last 20 trains to arrive at Danville Station, 15 were on time. What is the experimental probability that the next train to arrive will be on time? Write your answer as a fraction or whole number. P( on time )= ◻ Submit$

Of the last $20$ trains to arrive at Danville Station, $15$ were on time. What is the experimental probability that the next train to arrive will be on time? $\newline$ Write your answer as a fraction or whole number. $\newline$ $\mathrm{P}($ on time $)=$ $\square$ $\newline$ Submit

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Experimental probability

Full solution

Q. Of the last

20

trains to arrive at Danville Station,

15

were on time. What is the experimental probability that the next train to arrive will be on time?

\newline

Write your answer as a fraction or whole number.

\newline

\mathrm{P}(

on time

)=

\square

\newline

Submit

Identify Total Trains: Step $1$ : Identify the total number of trains and the number of trains that were on time. $\newline$ Total trains = $20$ $\newline$ Trains on time = $15$ $\newline$ We need to find the probability that the next train will be on time. $\newline$ Calculation: $P(\text{on time}) = \frac{\text{Number of trains on time}}{\text{Total number of trains}}$ $\newline$ = $\frac{15}{20}$
Calculate Probability: Step $2$ : Simplify the fraction to find the probability in simplest form. $\newline$ $\frac{15}{20}$ can be simplified by dividing both the numerator and the denominator by their greatest common divisor, which is $5$ . $\newline$ Calculation: \frac{15}{20} = \frac{(15/5)}{(20/5)}\(\newline= \frac{3}{4}\)

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