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Consider the following polynomial.\newlineq(x)=4x23x+12q(x)=4x^{2}-3x+12\newlineStep 22 of 22: Describe the behavior of the graph of q(x)q(x) as x±x \rightarrow \pm\infty.\newlineq(x)q(x)\rightarrow \square as xx \rightarrow -\infty

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Q. Consider the following polynomial.\newlineq(x)=4x23x+12q(x)=4x^{2}-3x+12\newlineStep 22 of 22: Describe the behavior of the graph of q(x)q(x) as x±x \rightarrow \pm\infty.\newlineq(x)q(x)\rightarrow \square as xx \rightarrow -\infty
  1. Identify Leading Term: To analyze the behavior of the graph of q(x)q(x) as xx approaches positive or negative infinity, we need to consider the leading term of the polynomial q(x)=4x23x+12q(x) = 4x^2 - 3x + 12, which is 4x24x^2. The leading term will dominate the behavior of the polynomial for large values of xx, both positive and negative.
  2. Behavior as xx approaches ++\infty: Since the leading coefficient of the leading term 4x24x^2 is positive, as xx approaches positive infinity (x+x \rightarrow +\infty), the value of 4x24x^2 will also approach positive infinity. Therefore, q(x)q(x) will approach positive infinity as well.
  3. Behavior as xx approaches -\infty: Similarly, as xx approaches negative infinity (xx \rightarrow -\infty), the value of 4x24x^2 will still approach positive infinity because the square of a negative number is positive. Therefore, q(x)q(x) will also approach positive infinity as xx approaches negative infinity.

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