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NOTES & LESSON: Grammer Celebrating Texas -... Question 11* The graph of a linear function is shown on the grid. Which equation is best represented by this graph? A y+2=(7)/(5)(x+7) B y-2=(7)/(5)(x-7) c y+2=(5)/(7)(x+7) D y-2=(5)/(7)(x-7) A

NOTES \& LESSON:\newlineGrammer\newlineCelebrating Texas -...\newlineQuestion 1111*\newlineThe graph of a linear function is shown on the grid.\newlineWhich equation is best represented by this graph?\newlineA y+2=75(x+7) y+2=\frac{7}{5}(x+7) \newlineB y−2=75(x−7) y-2=\frac{7}{5}(x-7) \newlinec y+2=57(x+7) y+2=\frac{5}{7}(x+7) \newlineD y−2=57(x−7) y-2=\frac{5}{7}(x-7) \newlineA

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Q. NOTES \& LESSON:\newlineGrammer\newlineCelebrating Texas -...\newlineQuestion 1111*\newlineThe graph of a linear function is shown on the grid.\newlineWhich equation is best represented by this graph?\newlineA y+2=75(x+7) y+2=\frac{7}{5}(x+7) \newlineB y−2=75(x−7) y-2=\frac{7}{5}(x-7) \newlinec y+2=57(x+7) y+2=\frac{5}{7}(x+7) \newlineD y−2=57(x−7) y-2=\frac{5}{7}(x-7) \newlineA
  1. Identify y-intercept: Identify the y-intercept from the graph. The line crosses the y-axis at (0,−2)(0, -2).
  2. Determine slope: Determine the slope by finding the change in yy over the change in xx between two clear points on the line. Using points (0,−2)(0, -2) and (5,5)(5, 5), the slope (mm) is calculated as m=5−(−2)5−0=75m = \frac{5 - (-2)}{5 - 0} = \frac{7}{5}.
  3. Formulate equation: Formulate the equation of the line using the slope-intercept form y=mx+by = mx + b, where mm is the slope and bb is the y-intercept. Plugging in the values, y=75x−2y = \frac{7}{5}x - 2.
  4. Compare with options: Compare the formulated equation with the given options. The correct equation must match the slope and yy-intercept identified. Option A, y+2=75(x+7)y + 2 = \frac{7}{5}(x + 7), rearranges to y=75x−2y = \frac{7}{5}x - 2, which matches our equation.

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