Nit.junesk 12 ors bookmaiksMure Menu StufiDragenFly MAX- Drift Hunterswitloniestion 2 of 10Write the equation for an exponential function, in the form y=a×bx, whose graph passes throt coordinate points (1,7.5) and (3,16.875).
Q. Nit.junesk 12 ors bookmaiksMure Menu StufiDragenFly MAX- Drift Hunterswitloniestion 2 of 10Write the equation for an exponential function, in the form y=a×bx, whose graph passes throt coordinate points (1,7.5) and (3,16.875).
General Form Identification: First, let's use the general form of an exponential function, y=a⋅bx. We need to find the values of a and b that will make the function pass through the points (1,7.5) and (3,16.875).
First Point Calculation: Plug in the coordinates of the first point (1,7.5) into the equation to get 7.5=a⋅b1, which simplifies to 7.5=a⋅b.
Second Point Calculation: Now plug in the coordinates of the second point (3,16.875) into the equation to get 16.875=a⋅b3.
Elimination of Variable: We now have two equations: 7.5=a×b and 16.875=a×b3. We can divide the second equation by the first to eliminate a and solve for b. So, (16.875/7.5)=b3/b, which simplifies to 2.25=b2.
Finding Value of b: To find b, we take the square root of 2.25, which gives us b=1.5.
Substitute b to Find a: Now that we have b, we can substitute it back into the first equation 7.5=a×b to find a. So, 7.5=a×1.5.
Final Exponential Function: Divide both sides by 1.5 to solve for a, which gives us a=1.57.5. This simplifies to a=5.
Final Exponential Function: Divide both sides by 1.5 to solve for a, which gives us a=1.57.5. This simplifies to a=5. Now we have both a and b, so the exponential function is y=5×1.5x.
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