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nat
res
He boxth 24 pupusas. Some were theese, and some mere pork.
He spent a tocal of 5136.00.
Cheese pupusas cost 
$5.50 each, and pork pupusas cost 56.00 acach.
How many of each variety did he buy?
Cheese Rupusas: 
◻ I I 
◻ ] Patk Pupusar: 
◻ -

nat\newlineres\newlineHe boxth 2424 pupusas. Some were theese, and some mere pork.\newlineHe spent a tocal of 51365136.0000.\newlineCheese pupusas cost $5.50 \$ 5.50 each, and pork pupusas cost 5656.0000 acach.\newlineHow many of each variety did he buy?\newlineCheese Rupusas: \square I I \square ] Patk Pupusar: \square -

Full solution

Q. nat\newlineres\newlineHe boxth 2424 pupusas. Some were theese, and some mere pork.\newlineHe spent a tocal of 51365136.0000.\newlineCheese pupusas cost $5.50 \$ 5.50 each, and pork pupusas cost 5656.0000 acach.\newlineHow many of each variety did he buy?\newlineCheese Rupusas: \square I I \square ] Patk Pupusar: \square -
  1. Identify Variables: Let's call the number of cheese pupusas cc and the number of pork pupusas pp. We have two equations: 11) c+p=24c + p = 24 (because he bought 2424 pupusas in total) 22) 5.50c+6.00p=136.005.50c + 6.00p = 136.00 (because this is the total amount spent on pupusas)
  2. Solve Equation 11: First, let's solve equation 11) for cc: c=24pc = 24 - p
  3. Substitute in Equation 22: Now, substitute cc in equation 22) with 24p24 - p: \newline5.50(24p)+6.00p=136.005.50(24 - p) + 6.00p = 136.00
  4. Solve for p: Do the math:\newline1325.50p+6.00p=136.00132 - 5.50p + 6.00p = 136.00\newline0.50p=136.001320.50p = 136.00 - 132\newline0.50p=4.000.50p = 4.00
  5. Find Value of p: Divide both sides by 0.500.50 to find pp:p=4.000.50p = \frac{4.00}{0.50}p=8p = 8
  6. Substitute pp in cc: Now, substitute pp back into the equation for cc:c=248c = 24 - 8c=16c = 16
  7. Final Answer: So, Nat bought 1616 cheese pupusas and 88 pork pupusas.

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