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Nana has a water purifier that filters 
(1)/(3) of the contaminants each hour. She used it to purify water that had 
(1)/(2) kilogram of contaminants.
Write a function that gives the remaining amount of contaminants in kilograms, 
C(t),t hours after Nana started purifying the water.

C(t)=

Nana has a water purifier that filters 13 \frac{1}{3} of the contaminants each hour. She used it to purify water that had 12 \frac{1}{2} kilogram of contaminants.\newlineWrite a function that gives the remaining amount of contaminants in kilograms, C(t),t C(t), t hours after Nana started purifying the water.\newlineC(t)= C(t)= \square

Full solution

Q. Nana has a water purifier that filters 13 \frac{1}{3} of the contaminants each hour. She used it to purify water that had 12 \frac{1}{2} kilogram of contaminants.\newlineWrite a function that gives the remaining amount of contaminants in kilograms, C(t),t C(t), t hours after Nana started purifying the water.\newlineC(t)= C(t)= \square
  1. Identify Contaminants and Rate: Step 11: Identify the initial amount of contaminants and the rate at which the purifier filters the contaminants. Nana starts with 12\frac{1}{2} kilogram of contaminants, and the purifier filters 13\frac{1}{3} of the contaminants each hour.
  2. Calculate Remaining Contaminants: Step 22: Since the purifier filters (1)/(3)(1)/(3) of the contaminants each hour, this means that each hour, (2)/(3)(2)/(3) of the contaminants remain. The function for the remaining contaminants will be a geometric decay function.
  3. Write Remaining Contaminants Function: Step 33: Write the function for the remaining amount of contaminants. The initial amount is (12)(\frac{1}{2}) kilogram, and after each hour, (23)(\frac{2}{3}) of the remaining contaminants are left. The function is C(t)=(initial amount)×(remaining fraction)tC(t) = (\text{initial amount}) \times (\text{remaining fraction})^t.
  4. Substitute Values into Function: Step 44: Substitute the known values into the function. The initial amount is (1)/(2)(1)/(2) kilogram, and the remaining fraction each hour is (2)/(3)(2)/(3). Therefore, the function is C(t)=(1/2)×(2/3)tC(t) = (1/2) \times (2/3)^t.
  5. Simplify Final Function: Step 55: Simplify the function if necessary. In this case, the function is already in its simplest form. So, the final function is C(t)=(12)(23)tC(t) = (\frac{1}{2}) \cdot (\frac{2}{3})^t.

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