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Name
Jaliyan
Date
Multiplying Fractions
2. The math club has 96 members. 
(1)/(8) of the members are fourth graders and th rest are fifth graders. How many math club members are fifth graders?
(A) 12
C 80
B 16
D 84
4. In which equation is the product greater than 3 ?

(3)/(4)

" A "1×(1)/(3)=(1)/(12)
B 
(3)/(2)×3

(1)/(12)

{:[C(1)/(12)×3],[(1)/(12)×(3)/(1)=(3)/(12)],[(1)/(12)×(1)/(3)=(1)/(36)]:}
D 
(9)/(10)×3

(3)/(2)x

(9)/(10)×(1)/(3)-(9)/(10)×(3)/(1)=(27)/(10)

Name\newlineJaliyan\newlineDate\newlineMultiplying Fractions\newline22. The math club has 9696 members. 18 \frac{1}{8} of the members are fourth graders and th rest are fifth graders. How many math club members are fifth graders?\newline(A) 1212\newlineC 8080\newlineB 1616\newlineD 8484\newline44. In which equation is the product greater than 33 ?\newline34 \frac{3}{4} \newline A 1×13=112 \text { A } 1 \times \frac{1}{3}=\frac{1}{12} \newlineB 32×3 \frac{3}{2} \times 3 \newline112 \frac{1}{12} \newlineC112×3112×31=312112×13=136 \begin{array}{l} C \frac{1}{12} \times 3 \\ \frac{1}{12} \times \frac{3}{1}=\frac{3}{12} \\ \frac{1}{12} \times \frac{1}{3}=\frac{1}{36} \end{array} \newlineD 910×3 \frac{9}{10} \times 3 \newline32x \frac{3}{2} x \newline910×13910×31=2710 \frac{9}{10} \times \frac{1}{3}-\frac{9}{10} \times \frac{3}{1}=\frac{27}{10}

Full solution

Q. Name\newlineJaliyan\newlineDate\newlineMultiplying Fractions\newline22. The math club has 9696 members. 18 \frac{1}{8} of the members are fourth graders and th rest are fifth graders. How many math club members are fifth graders?\newline(A) 1212\newlineC 8080\newlineB 1616\newlineD 8484\newline44. In which equation is the product greater than 33 ?\newline34 \frac{3}{4} \newline A 1×13=112 \text { A } 1 \times \frac{1}{3}=\frac{1}{12} \newlineB 32×3 \frac{3}{2} \times 3 \newline112 \frac{1}{12} \newlineC112×3112×31=312112×13=136 \begin{array}{l} C \frac{1}{12} \times 3 \\ \frac{1}{12} \times \frac{3}{1}=\frac{3}{12} \\ \frac{1}{12} \times \frac{1}{3}=\frac{1}{36} \end{array} \newlineD 910×3 \frac{9}{10} \times 3 \newline32x \frac{3}{2} x \newline910×13910×31=2710 \frac{9}{10} \times \frac{1}{3}-\frac{9}{10} \times \frac{3}{1}=\frac{27}{10}
  1. Calculate Fourth Graders: Calculate the number of fourth graders by taking 18\frac{1}{8} of the total members.\newline18×96=12\frac{1}{8} \times 96 = 12.
  2. Calculate Fifth Graders: Subtract the number of fourth graders from the total to find the number of fifth graders. 9612=8496 - 12 = 84.
  3. Check Option A: Check option A: 1×13=131 \times \frac{1}{3} = \frac{1}{3}, which is not greater than 33.
  4. Check Option B: Check option B: 32×3=92\frac{3}{2} \times 3 = \frac{9}{2}, which is 4.54.5 and greater than 33.

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