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Let 
y=3^(x).
Find 
(d^(2)y)/(dx^(2)).

(d^(2)y)/(dx^(2))=

Let y=3x y=3^{x} .\newlineFind d2ydx2 \frac{d^{2} y}{d x^{2}} .\newlined2ydx2= \frac{d^{2} y}{d x^{2}}=

Full solution

Q. Let y=3x y=3^{x} .\newlineFind d2ydx2 \frac{d^{2} y}{d x^{2}} .\newlined2ydx2= \frac{d^{2} y}{d x^{2}}=
  1. Find First Derivative: To find the second derivative of yy with respect to xx, we first need to find the first derivative. The function y=3xy = 3^x is an exponential function, and the derivative of an exponential function with base aa (where aa is a constant) and exponent xx is given by the formula dydx=axln(a)\frac{dy}{dx} = a^x \cdot \ln(a). In this case, a=3a = 3, so we apply this formula to find the first derivative.\newlineCalculation: dydx=3xln(3)\frac{dy}{dx} = 3^x \cdot \ln(3)
  2. Differentiate Again: Now that we have the first derivative, we need to differentiate it once more to find the second derivative. We apply the same rule for differentiation of an exponential function.\newlineCalculation: d2ydx2=ddx(3xln(3))=ln(3)ddx(3x)\frac{d^2y}{dx^2} = \frac{d}{dx} (3^x \cdot \ln(3)) = \ln(3) \cdot \frac{d}{dx} (3^x)\newlineSince ln(3)\ln(3) is a constant, it remains unchanged during differentiation. The derivative of 3x3^x with respect to xx is again 3xln(3)3^x \cdot \ln(3).
  3. Combine to Find Second Derivative: Combining the constant ln(3)\ln(3) with the derivative of 3x3^x, we get the second derivative.\newlineCalculation: d2ydx2=ln(3)×(3x×ln(3))=(ln(3))2×3x\frac{d^2y}{dx^2} = \ln(3) \times (3^x \times \ln(3)) = (\ln(3))^2 \times 3^x