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Uuestion 1

Which expression is equivalent to 
(60m^(-2)n^(6))/(5m^(-4)n^(-2)) for all values of 
m and 
n where th expression is defined?


12m^(2)n^(8)quad(12n^(5))/(m^(6))
A.
B.

My Drive - Google Dr...\newlineComputer science\newlineClasswork\newlineInbox - anton\newlinentonio.canas.183183@k1212.friscoisd.org Switch account\newlineour email will be recorded when you submit this form\newlineIndicates required question\newlineUuestion 11\newline11. Which expression is equivalent to 60m2n65m4n2 \frac{60 m^{-2} n^{6}}{5 m^{-4} n^{-2}} for all values of m m and n n where th expression is defined?\newline12m2n812n5m6 12 m^{2} n^{8} \quad \frac{12 n^{5}}{m^{6}} \newlineA.\newlineB.

Full solution

Q. My Drive - Google Dr...\newlineComputer science\newlineClasswork\newlineInbox - anton\newlinentonio.canas.183183@k1212.friscoisd.org Switch account\newlineour email will be recorded when you submit this form\newlineIndicates required question\newlineUuestion 11\newline11. Which expression is equivalent to 60m2n65m4n2 \frac{60 m^{-2} n^{6}}{5 m^{-4} n^{-2}} for all values of m m and n n where th expression is defined?\newline12m2n812n5m6 12 m^{2} n^{8} \quad \frac{12 n^{5}}{m^{6}} \newlineA.\newlineB.
  1. Simplify coefficients: First, simplify the coefficients by dividing 6060 by 55, which gives us 1212.
  2. Add exponents for mm: Next, add the exponents for mm because when you divide powers with the same base, you subtract the exponents: (2)(4)=(2)+4=2(-2) - (-4) = (-2) + 4 = 2. So, m2/m4m^{-2} / m^{-4} becomes m2m^{2}.
  3. Add exponents for \newline: Then, do the same for \newline: 66 - (2-2) = 66 + 22 = 88. So, \newline^{(66)} / \newline^{(2-2)} becomes \newline^{(88)}.
  4. Combine coefficients and exponents: Now, combine the simplified coefficients and the new exponents for mm and nn to get the final answer: 12m2n812m^{2}n^{8}.

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