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Multiply. Write your answer (3g-2)/(g^(2)-1)*(g+1)

Multiply. Write your answer\newline3g−2g2−1⋅(g+1) \frac{3 g-2}{g^{2}-1} \cdot(g+1)

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Full solution

Q. Multiply. Write your answer\newline3g−2g2−1⋅(g+1) \frac{3 g-2}{g^{2}-1} \cdot(g+1)
  1. Rewrite multiplication: Rewrite the multiplication of the two fractions. So, (3g−2)/(g2−1)×(g+1)=(3g−2)×(g+1)/(g2−1)(3g-2)/(g^2-1) \times (g+1) = (3g-2) \times (g+1) / (g^2-1).
  2. Factor denominator: Factor the denominator g2−1g^2-1 to (g−1)(g+1)(g-1)(g+1).
  3. Cancel common factors: Cancel out the common factors in the numerator and the denominator. The (g+1)(g+1) in the numerator and denominator cancel each other out. So, (3g−2)×(g+1)/(g2−1)(3g-2) \times (g+1) / (g^2-1) becomes (3g−2)/(g−1)(3g-2) / (g-1).
  4. Final answer: The final answer is (3g−2)/(g−1)(3g-2) / (g-1).

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