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Multiply. Simplify your answer.\newline7hj14h2j2×8h2\frac{7hj}{14h^2j^2} \times 8h^2

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Q. Multiply. Simplify your answer.\newline7hj14h2j2×8h2\frac{7hj}{14h^2j^2} \times 8h^2
  1. Write Problem & Identify Terms: Write down the problem and identify the terms that can be simplified. We have the expression (7hj)/(14h2j2)×8h2(7hj)/(14h^2j^2) \times 8h^2. We can simplify by canceling out common factors in the numerator and the denominator.
  2. Cancel Common Factors: Cancel out the common factors. The hh in the numerator can cancel with one hh from h2h^2 in the denominator, and the jj in the numerator can cancel with one jj from j2j^2 in the denominator. Also, the 77 in the numerator can be divided by 1414 in the denominator to simplify further.
  3. Perform Simplification: Perform the simplification. (714)(\frac{7}{14}) reduces to (12)(\frac{1}{2}), hh2\frac{h}{h^2} reduces to (1h)(\frac{1}{h}), and jj2\frac{j}{j^2} reduces to (1j)(\frac{1}{j}). So, we have (12)×(1h)×(1j)×8h2(\frac{1}{2}) \times (\frac{1}{h}) \times (\frac{1}{j}) \times 8h^2.
  4. Multiply Remaining Terms: Multiply the remaining terms. We have (12)×(1h)×(1j)×8h2=(82)×h2h×1j=4h×1j=4hj(\frac{1}{2}) \times (\frac{1}{h}) \times (\frac{1}{j}) \times 8h^2 = (\frac{8}{2}) \times \frac{h^2}{h} \times \frac{1}{j} = 4h \times \frac{1}{j} = \frac{4h}{j}.

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