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Multiply. Simplify your answer. \newline6k16j2k2×20j\frac{6k}{16j^2k^2} \times 20j

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Full solution

Q. Multiply. Simplify your answer. \newline6k16j2k2×20j\frac{6k}{16j^2k^2} \times 20j
  1. Rewrite multiplication: Rewrite the multiplication of the two fractions. We have (6k16j2k2)×(20j1)(\frac{6k}{16j^2k^2}) \times (\frac{20j}{1}).
  2. Multiply numerators and denominators: Multiply the numerators together and the denominators together. So, (6k×20j)/(16j2k2×1)(6k \times 20j) / (16j^2k^2 \times 1).
  3. Perform multiplication: Perform the multiplication in the numerator and denominator. This gives us (120jk)/(16j2k2)(120jk) / (16j^2k^2).
  4. Simplify fraction by canceling: Simplify the fraction by canceling out common factors. The number 1616 can be divided by 44, and 120120 can be divided by 44, resulting in (30jk)/(4j2k2)(30jk) / (4j^2k^2). Also, we can cancel out one jj from the numerator and denominator, and one kk from the numerator and denominator. This results in (30)/(4jk)(30) / (4jk).
  5. Further simplify fraction: Simplify the fraction further by dividing the numerator and the denominator by their greatest common divisor, which is 44. This gives us (30/4)/(jk)(30/4) / (jk). Simplifying 30/430/4 gives us 7.57.5, so the final simplified form is 7.5/jk7.5/jk.

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