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Multiply. Simplify your answer.\newline15v23v×4v2\frac{15v^2}{3v} \times 4v^2

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Full solution

Q. Multiply. Simplify your answer.\newline15v23v×4v2\frac{15v^2}{3v} \times 4v^2
  1. Identify Terms and Rewrite: Identify the terms to be multiplied and rewrite the multiplication expression.\newlineWe have the expression (15v23v)×(4v2)(\frac{15v^2}{3v}) \times (4v^2). We will multiply the numerators together and the denominators together.
  2. Simplify Before Multiplying: Simplify the expression before multiplying.\newlineWe can simplify 15v23v\frac{15v^2}{3v} by canceling a common factor of 3v3v from the numerator and the denominator. This gives us 5v5v. Now we have 5v×4v25v \times 4v^2.
  3. Multiply Simplified Terms: Multiply the simplified terms.\newlineMultiplying 5v5v by 4v24v^2 gives us 5×4×v×v25 \times 4 \times v \times v^2, which is 20v320v^3.
  4. Check for Further Simplification: Check for any further simplification.\newlineThe expression 20v320v^3 is already in its simplest form. There are no common factors to cancel, and the expression is fully multiplied out.
  5. Write Final Answer: Write the final answer.\newlineThe simplified result of the multiplication is 20v320v^3.

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