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Ms. Bell's mathematics class consists of 8 sophomores, 13 juniors, and 9 seniors. How many different ways can Ms. Bell create a 3-member committee of sophomores if each sophomore has an equal chance of being selected?
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Ms. Bell's mathematics class consists of 88 sophomores, 1313 juniors, and 99 seniors. How many different ways can Ms. Bell create a 33-member committee of sophomores if each sophomore has an equal chance of being selected?\newlineAnswer:

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Q. Ms. Bell's mathematics class consists of 88 sophomores, 1313 juniors, and 99 seniors. How many different ways can Ms. Bell create a 33-member committee of sophomores if each sophomore has an equal chance of being selected?\newlineAnswer:
  1. Define Combination Formula: To determine the number of different ways to create a 33-member committee from the 88 sophomores, we need to use the combination formula, which is defined as C(n,k)=n!k!(nk)!C(n, k) = \frac{n!}{k!(n - k)!}, where nn is the total number of items to choose from, kk is the number of items to choose, and “!!” denotes factorial.\newlineIn this case, n=8n = 8 (the number of sophomores) and k=3k = 3 (the number of members for the committee).
  2. Calculate Factorial of nn: First, we calculate the factorial of nn, which is 8!8! (88 factorial).8!=8×7×6×5×4×3×2×1=40,3208! = 8 \times 7 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 40,320
  3. Calculate Factorial of kk: Next, we calculate the factorial of kk, which is 3!3! (33 factorial).3!=3×2×1=63! = 3 \times 2 \times 1 = 6
  4. Calculate Factorial of (nk)(n - k): Then, we calculate the factorial of (nk)(n - k), which is (83)!(8 - 3)! or 5!5! (55 factorial).\newline5!=5×4×3×2×1=1205! = 5 \times 4 \times 3 \times 2 \times 1 = 120
  5. Use Combination Formula: Now, we can use the combination formula to find the number of different ways to create the committee: C(8,3)=8!3!(83)!=40,3206×120C(8, 3) = \frac{8!}{3!(8 - 3)!} = \frac{40,320}{6 \times 120}
  6. Simplify Calculation: We simplify the calculation by dividing 40,32040,320 by 66 and then by 120120: \newline40,320/6=6,72040,320 / 6 = 6,720\newline6,720/120=566,720 / 120 = 56
  7. Final Result: Therefore, there are 5656 different ways Ms. Bell can create a 33-member committee of sophomores.

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