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Mrs landau has two daughters, serval and lynx. The highest common factor and the lowest common multiple of their age are 33 and 168168 respectively. If serval is 33 years older than her sister, find serval’s age

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Q. Mrs landau has two daughters, serval and lynx. The highest common factor and the lowest common multiple of their age are 33 and 168168 respectively. If serval is 33 years older than her sister, find serval’s age
  1. Denote Ages: Let's denote Serval's age as SS and Lynx's age as LL. We know that S=L+3S = L + 3.
  2. HCF and LCM: The highest common factor (HCF) of their ages is 33. This means that both SS and LL are multiples of 33.
  3. Equation Setup: The lowest common multiple (LCM) of their ages is 168168. Since LCM of two numbers aa and bb is given by (a×b)/HCF(a,b)(a \times b) / \text{HCF}(a, b), we can write the equation S×L=168×3S \times L = 168 \times 3.
  4. Substitution: Substitute S=L+3S = L + 3 into the equation: (L+3)L=504(L + 3) \cdot L = 504.
  5. Expand Equation: Expand the equation: L2+3L=504L^2 + 3L = 504.
  6. Rearrange Quadratic: Rearrange the equation to form a quadratic equation: L2+3L504=0L^2 + 3L - 504 = 0.
  7. Factor Quadratic: Factor the quadratic equation: (L+21)(L24)=0(L + 21)(L - 24) = 0.
  8. Solve for L: Solve for L: L=21L = -21 or L=24L = 24. Since age cannot be negative, L=24L = 24.
  9. Find Serval's Age: Now, find Serval's age using S=L+3S = L + 3: S=24+3S = 24 + 3.
  10. Calculate Serval's Age: Calculate Serval's age: S=27S = 27.

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