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Mrs. Avery makes note of the different types of plants in her garden and creates a bar graph to display the data.
MRS. AVERY'S GARDEN
#1: There are one-fourth the number of peppers as there are lettuce plants.
#2: The number of lettuce and pepper plants is equal to the number of tomato and strawberry plants.
#3: Fifty percent of the plants are lettuce plants.

Mrs. Avery makes note of the different types of plants in her garden and creates a bar graph to display the data. $\newline$ MRS. AVERY'S GARDEN $\newline$ \# $1$ : There are one-fourth the number of peppers as there are lettuce plants. $\newline$ \# $2$ : The number of lettuce and pepper plants is equal to the number of tomato and strawberry plants. $\newline$ \# $3$ : Fifty percent of the plants are lettuce plants.

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Evaluate two-variable equations: word problems

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Q. Mrs. Avery makes note of the different types of plants in her garden and creates a bar graph to display the data.

\newline

MRS. AVERY'S GARDEN

\newline

\#

1

: There are one-fourth the number of peppers as there are lettuce plants.

\newline

\#

2

: The number of lettuce and pepper plants is equal to the number of tomato and strawberry plants.

\newline

\#

3

: Fifty percent of the plants are lettuce plants.

Calculate Lettuce Plants: Let's denote the total number of plants as $P$ . According to the problem, $50$ % of the plants are lettuce plants. So, the number of lettuce plants $L$ is: $\newline$ $L = 0.5P$
Calculate Pepper Plants: From the first point, there are one-fourth the number of peppers as there are lettuce plants. So, the number of pepper plants $Pe$ is: $\newline$ $Pe = \frac{1}{4}L$ $\newline$ $Pe = \frac{1}{4}(0.5P)$ $\newline$ $Pe = 0.125P$
Calculate Tomato and Strawberry Plants: The second point states that the number of lettuce and pepper plants combined is equal to the number of tomato and strawberry plants combined. Let $T$ be the number of tomato plants and $S$ be the number of strawberry plants. Then: $\newline$ $L + Pe = T + S$ $\newline$ $0.5P + 0.125P = T + S$ $\newline$ $0.625P = T + S$
Calculate Total Plants: Since $L$ , $Pe$ , $T$ , and $S$ together make up all the plants, we have: $\newline$ $L + Pe + T + S = P$ $\newline$ $0.5P + 0.125P + T + S = P$ $\newline$ $0.625P + T + S = P$ $\newline$ $T + S = P - 0.625P$ $\newline$ $T + S = 0.375P$

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