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Mr. Miller presented his class with the followi

(7.5*10^(4))(p*10^(q))=1.5*10^(8)
What are possible values of 
p and 
q ?

{:[p=],[q=]:}

Mr. Miller presented his class with the followi\newline(7.5104)(p10q)=1.5108 \left(7.5 \cdot 10^{4}\right)\left(p \cdot 10^{q}\right)=1.5 \cdot 10^{8} \newlineWhat are possible values of p p and q q ?\newlinep=q= \begin{array}{l} p= \\ q= \end{array}

Full solution

Q. Mr. Miller presented his class with the followi\newline(7.5104)(p10q)=1.5108 \left(7.5 \cdot 10^{4}\right)\left(p \cdot 10^{q}\right)=1.5 \cdot 10^{8} \newlineWhat are possible values of p p and q q ?\newlinep=q= \begin{array}{l} p= \\ q= \end{array}
  1. Multiply Coefficients and Powers: First, let's multiply the coefficients (7.57.5 and pp) and the powers of 1010 separately.\newline7.5×p=1.57.5 \times p = 1.5
  2. Solve for p: Now, let's solve for pp by dividing both sides by 7.57.5.p=1.57.5p = \frac{1.5}{7.5}p=0.2p = 0.2
  3. Multiply Powers of 1010: Next, we multiply the powers of 1010. 104+q=10810^{4+q} = 10^{8}
  4. Solve for q: Now, let's solve for q by equating the exponents.\newline4+q=84 + q = 8\newlineq=84q = 8 - 4\newlineq=4q = 4

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