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Mr. Lynch brought in 88 solid colored eggs for his Physics classes. 66 of the eggs were green. If Mr. Lynch randomly chose 55 eggs for his first class to use in an egg drop experiment, what is the probability that all of them are green?\newlineWrite your answer as a decimal rounded to four decimal places.._________

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Q. Mr. Lynch brought in 88 solid colored eggs for his Physics classes. 66 of the eggs were green. If Mr. Lynch randomly chose 55 eggs for his first class to use in an egg drop experiment, what is the probability that all of them are green?\newlineWrite your answer as a decimal rounded to four decimal places.._________
  1. Total Eggs Selection Calculation: Total number of eggs: 88\newlineEggs to choose for the experiment: 55\newlineCalculate total possible outcomes using combinations.\newlineTotal outcomes: (85)\binom{8}{5}
  2. Total Possible Outcomes Calculation: Find the value of (85)\binom{8}{5}.\newline (85)=8!5!(85)!=8!5!3!=8×7×6×5!5!×3×2×1=56\binom{8}{5} = \frac{8!}{5!(8-5)!} = \frac{8!}{5!3!} = \frac{8 \times 7 \times 6 \times 5!}{5! \times 3 \times 2 \times 1} = 56
  3. Green Eggs Selection Calculation: Number of green eggs: 66\newlineNumber of chosen green eggs: 55\newlineCalculate favorable outcomes using combinations.\newlineFavorable outcomes: 6C5_{6}C_{5}
  4. Probability Calculation: Find the value of (65)\binom{6}{5}. (65)=6!5!(65)!=6!5!1!=6×5!5!×1=6\binom{6}{5} = \frac{6!}{5!(6-5)!} = \frac{6!}{5!1!} = \frac{6 \times 5!}{5! \times 1} = 6
  5. Probability Calculation: Find the value of (65)\binom{6}{5}.\newline(65)=6!5!(65)!\binom{6}{5} = \frac{6!}{5!(6-5)!}\newline=6!5!1!= \frac{6!}{5!1!}\newline=6×5!5!×1= \frac{6 \times 5!}{5! \times 1}\newline=6= 6Calculate the probability that all chosen eggs are green.\newlineProbability = Favorable outcomes / Total possible outcomes\newline=656= \frac{6}{56}\newline0.1071\approx 0.1071

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