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Mr. Free's science class measures rain for two months. In the first month, there was 
(2)/(5) of an inch of rain. In the second month, there was 
(1)/(5) of an inch of rain. What was the total amount of rain over the two months? How much would it have to rain in the third month to reach 
(4)/(5) of an inch for all three months?
Answer: 
qquad
Explain: 
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qquad

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35

Mr. Free's science class measures rain for two months. In the first month, there was 25\frac{2}{5} of an inch of rain. In the second month, there was 15\frac{1}{5} of an inch of rain. What was the total amount of rain over the two months? How much would it have to rain in the third month to reach 45\frac{4}{5} of an inch for all three months?\newlineAnswer: \newline\qquad\newlineExplain: \newline\qquad\newline\qquad\newline\qquad\newline3535

Full solution

Q. Mr. Free's science class measures rain for two months. In the first month, there was 25\frac{2}{5} of an inch of rain. In the second month, there was 15\frac{1}{5} of an inch of rain. What was the total amount of rain over the two months? How much would it have to rain in the third month to reach 45\frac{4}{5} of an inch for all three months?\newlineAnswer: \newline\qquad\newlineExplain: \newline\qquad\newline\qquad\newline\qquad\newline3535
  1. Add Rainfall Calculation: Step 11: Add the rainfall from the first two months.\newlineCalculation: (25)(\frac{2}{5}) inch + (15)(\frac{1}{5}) inch = (35)(\frac{3}{5}) inch.
  2. Calculate Additional Rain Needed: Step 22: Determine how much more rain is needed in the third month to reach (45)(\frac{4}{5}) inch total.\newlineCalculation: (45)(\frac{4}{5}) inch - (35)(\frac{3}{5}) inch = (15)(\frac{1}{5}) inch.

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