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Measurements of a room are 
7m50cm,6m& 
3m75cm. Find the length of the longest rod that can measure all the three dimensions of the room.

Measurements of a room are 7 m50 cm,6 m& 7\mathrm{~m} 50 \mathrm{~cm}, 6 \mathrm{~m} \& 3 m75 cm 3 \mathrm{~m} 75 \mathrm{~cm} . Find the length of the longest rod that can measure all the three dimensions of the room.

Full solution

Q. Measurements of a room are 7 m50 cm,6 m& 7\mathrm{~m} 50 \mathrm{~cm}, 6 \mathrm{~m} \& 3 m75 cm 3 \mathrm{~m} 75 \mathrm{~cm} . Find the length of the longest rod that can measure all the three dimensions of the room.
  1. Convert to centimeters: Convert all measurements to centimeters for uniformity.\newline7m50cm=750cm7\text{m} 50\text{cm} = 750\text{cm}, 6m=600cm6\text{m} = 600\text{cm}, 3m75cm=375cm3\text{m} 75\text{cm} = 375\text{cm}.
  2. Find GCD for longest rod: Find the greatest common divisor (GCD) of the three measurements to determine the longest rod that can measure all dimensions.\newlineGCD of 750750, 600600, and 375375.\newlineUsing prime factorization:\newline750=2×3×53750 = 2 \times 3 \times 5^3\newline600=22×3×52600 = 2^2 \times 3 \times 5^2\newline375=3×53375 = 3 \times 5^3\newlineCommon factors are 33 and 525^2.\newlineGCD = 3×52=75cm3 \times 5^2 = 75\,\text{cm}.

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