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MCR3U - OPTIONAL ASSIGNMENT
Part A : choose one

A culture has 570 bacteria. The number of bacteria doubles every 
12h. How long will it take to have 2152 bacteria in the culture?


2x^(2)-3x

MCR33U - OPTIONAL ASSIGNMENT\newlinePart A : choose one\newline11. A culture has 570570 bacteria. The number of bacteria doubles every 12 h 12 \mathrm{~h} . How long will it take to have 21522152 bacteria in the culture?\newline2x23x 2 x^{2}-3 x

Full solution

Q. MCR33U - OPTIONAL ASSIGNMENT\newlinePart A : choose one\newline11. A culture has 570570 bacteria. The number of bacteria doubles every 12 h 12 \mathrm{~h} . How long will it take to have 21522152 bacteria in the culture?\newline2x23x 2 x^{2}-3 x
  1. Denote Initial Bacteria Number: Let's denote the initial number of bacteria as B0B_0 and the number of bacteria after tt hours as B(t)B(t). The formula for exponential growth is B(t)=B0×2(t/T)B(t) = B_0 \times 2^{(t/T)}, where TT is the doubling time in hours.
  2. Set Up Exponential Growth Formula: We know B0=570B_0 = 570, B(t)=2152B(t) = 2152, and T=12T = 12. We need to solve for tt. So, we set up the equation 2152=570×2t/122152 = 570 \times 2^{t/12}.
  3. Isolate Exponential Part: To isolate the exponential part, we divide both sides by 570570: 2152/570=2t/122152 / 570 = 2^{t/12}.
  4. Calculate Left Side: Calculating the left side gives us 2152/570=3.772152 / 570 = 3.77 (rounded to two decimal places).
  5. Take Natural Logarithm: Now we need to solve for tt in the equation 3.77=2t123.77 = 2^{\frac{t}{12}}. We can do this by taking the logarithm of both sides. Let's use the natural logarithm (ln): ln(3.77)=ln(2t12)\ln(3.77) = \ln(2^{\frac{t}{12}}).
  6. Rewrite Equation with Logarithms: Using the property of logarithms that ln(ab)=bln(a)\ln(a^b) = b\cdot\ln(a), we can rewrite the equation as ln(3.77)=(t12)ln(2)\ln(3.77) = \left(\frac{t}{12}\right)\cdot\ln(2).
  7. Solve for t: Now we solve for t: t=(ln(3.77)/ln(2))×12t = (\ln(3.77) / \ln(2)) \times 12.
  8. Perform Calculation: Calculating the right side gives us t=(ln(3.77)/ln(2))×12=(1.327/0.693)×12t = (\ln(3.77) / \ln(2)) \times 12 = (1.327 / 0.693) \times 12.
  9. Round Up to Nearest Multiple: After performing the calculation, we get t=(1.327/0.693)×12=22.98t = (1.327 / 0.693) \times 12 = 22.98 hours. However, since the bacteria can only double at 1212-hour intervals, we need to round up to the nearest multiple of 1212. So, t=24t = 24 hours.