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Trigonometric Identities and Equations
Sum and difference identities: Problem type 3
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Use the information given below to find 
cos(alpha-beta).

cos alpha=(3)/(5), with 
alpha in quadrant I

tan beta=(3)/(4), with 
beta in quadrant III
Give the exact answer, not a decimal approximation.

cos(alpha-beta)=

◻

◻

◻

sqrt◻
[Aa

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Explanation
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Math Al\newlineBest Al Homework Hel\newlineLogging in\newlineA\newlineALEKS - Jameson Colle\newlineByteLearn\newlinehttps://Www-awu.aleks.com/alekscgi/y/lsl.exe/1010_u-IgNslkasNW88D...\newlineImport favorites\newlineMVNU Students Ho...\newlineA\newlineALEKS - Jameson C...\newlineTrigonometric Identities and Equations\newlineSum and difference identities: Problem type 33\newlineJameson\newlineEspañol\newlineUse the information given below to find cos(αβ) \cos (\alpha-\beta) .\newlinecosα=35 \cos \alpha=\frac{3}{5} , with α \alpha in quadrant I\newlinetanβ=34 \tan \beta=\frac{3}{4} , with β \beta in quadrant III\newlineGive the exact answer, not a decimal approximation.\newlinecos(αβ)= \cos (\alpha-\beta)= \newline \square \newline \square \newline \square \newline \sqrt{\square} \newline[Aa\newline \square \newlineExplanation\newlineCheck\newlineC 20242024 McGraw Hill LLC. All Rights Reserved.\newlineTerms of Use\newlinePrivacy Center\newlineAccessibility\newlineType here to search

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Q. Math Al\newlineBest Al Homework Hel\newlineLogging in\newlineA\newlineALEKS - Jameson Colle\newlineByteLearn\newlinehttps://Www-awu.aleks.com/alekscgi/y/lsl.exe/1010_u-IgNslkasNW88D...\newlineImport favorites\newlineMVNU Students Ho...\newlineA\newlineALEKS - Jameson C...\newlineTrigonometric Identities and Equations\newlineSum and difference identities: Problem type 33\newlineJameson\newlineEspañol\newlineUse the information given below to find cos(αβ) \cos (\alpha-\beta) .\newlinecosα=35 \cos \alpha=\frac{3}{5} , with α \alpha in quadrant I\newlinetanβ=34 \tan \beta=\frac{3}{4} , with β \beta in quadrant III\newlineGive the exact answer, not a decimal approximation.\newlinecos(αβ)= \cos (\alpha-\beta)= \newline \square \newline \square \newline \square \newline \sqrt{\square} \newline[Aa\newline \square \newlineExplanation\newlineCheck\newlineC 20242024 McGraw Hill LLC. All Rights Reserved.\newlineTerms of Use\newlinePrivacy Center\newlineAccessibility\newlineType here to search
  1. Calculate rolls needed: Calculate the number of rolls by dividing the total amount of tape needed by the amount of tape on each roll. 8,000cm÷2,000cm/roll=4rolls8,000 \, \text{cm} \div 2,000 \, \text{cm}/\text{roll} = 4 \, \text{rolls}
  2. Verify calculation: Check the calculation to ensure no mistakes were made. 8,0008,000 divided by 2,0002,000 indeed equals 44.

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