Resourcesdown chevron
Testimonials
Plans
Sign in
Sign up
Resourcesright arrow
Testimonials
Plans
Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Martene got a small aquarium for her birthday. The aquarium is a right rectangular prism 18.5cm long by 15cm wide. Martene put 3885cm^(3) of water in the aquarium. How deep is the water in the aquarium? cm

Martene got a small aquarium for her birthday. The aquarium is a right rectangular prism 18.5 cm 18.5 \mathrm{~cm} long by 15 cm 15 \mathrm{~cm} wide. Martene put 3885 cm3 3885 \mathrm{~cm}^{3} of water in the aquarium.\newlineHow deep is the water in the aquarium?\newlinecm

View step-by-step helpView step-by-step help
Homeright chevron icon
Math Problemsright chevron icon
Algebra 2right chevron icon
Pythagorean Theorem and its converseright chevron icon

Full solution

Q. Martene got a small aquarium for her birthday. The aquarium is a right rectangular prism 18.5 cm 18.5 \mathrm{~cm} long by 15 cm 15 \mathrm{~cm} wide. Martene put 3885 cm3 3885 \mathrm{~cm}^{3} of water in the aquarium.\newlineHow deep is the water in the aquarium?\newlinecm
  1. Denote Depth as 'd': Let's denote the depth of the water in the aquarium as dd in centimeters. The volume VV of water in a right rectangular prism (the shape of the aquarium) is given by the formula V=length×width×depthV = \text{length} \times \text{width} \times \text{depth}. We know the volume of water, the length, and the width of the aquarium, so we can solve for the depth.
  2. Calculate Volume Equation: Given the volume of water V=3885 cm3V = 3885 \, \text{cm}^3, the length l=18.5 cml = 18.5 \, \text{cm}, and the width w=15 cmw = 15 \, \text{cm}, we can set up the equation 3885=18.5×15×d3885 = 18.5 \times 15 \times d to find the depth dd.
  3. Set Up Equation: Now we solve for dd by dividing both sides of the equation by the product of the length and width: d=3885(18.5×15)d = \frac{3885}{(18.5 \times 15)}.
  4. Solve for Depth: Performing the calculation gives us d=3885277.5d = \frac{3885}{277.5}.
  5. Calculate Final Depth: Calculating the division, we get d≈14d \approx 14. Therefore, the depth of the water in the aquarium is approximately 1414 centimeters.

More problems from Pythagorean Theorem and its converse

Question
Find all solutions with 0∘≤θ≤180∘0^\circ \leq \theta \leq 180^\circ. Give the exact answer(s) in simplest form. If there are multiple answers, separate them with commas.\newlinecos⁡(θ)=−1\cos(\theta) = -1\newline‾∘\underline{\hspace{2em}}^\circ
Get tutor helpright-arrow

Posted 2 months ago

Question
Kimi's school is 1515 kilometers west of her house and 88 kilometers south of her friend Franklin's house. Every day, Kimi bicycles from her house to her school. After school, she bicycles from her school to Franklin's house. Before dinner, she bicycles home on a bike path that goes straight from Franklin's house to her own house. How far does Kimi bicycle each day?\newline_____\_\_\_\_\_ kilometers
Get tutor helpright-arrow

Posted 2 months ago

Question
Evaluate. Write your answer as an integer or as a decimal rounded to the nearest hundredth.\newlinecos⁡35∘=\cos 35^\circ = __
Get tutor helpright-arrow

Posted 2 months ago

Question
Find all solutions with −90∘≤θ≤90∘-90^\circ \leq \theta \leq 90^\circ. Give the exact answer(s) in simplest form. If there are multiple answers, separate them with commas.\newlinecsc⁡(θ)=−1\csc(\theta) = -1\newline____ ∘\_\_\_\_\,^\circ
Get tutor helpright-arrow

Posted 2 months ago

Question
Evaluate. Write your answer in simplified, rationalized form. Do not round.\newlinecot⁡30∘=\cot 30^\circ = ______
Get tutor helpright-arrow

Posted 2 months ago

Question
The terminal side of an angle θ\theta in standard position intersects the unit circle at (8485,1385)(\frac{84}{85}, \frac{13}{85}). What is cos⁡(θ)\cos(\theta)?\newlineWrite your answer in simplified, rationalized form.\newline______
Get tutor helpright-arrow

Posted 2 months ago

Question
−90∘<θ<90∘-90^\circ < \theta < 90^\circ. Find the value of θ\theta in degrees.\newlinetan⁡(θ)=0\tan(\theta) = 0\newlineWrite your answer in simplified, rationalized form. Do not round.\newlineθ=\theta = ____∘^\circ\newline
Get tutor helpright-arrow

Posted 2 months ago

Question
Evaluate. Write your answer in simplified, rationalized form. Do not round.\newlinecsc⁡60∘=\csc 60^\circ = ______
Get tutor helpright-arrow

Posted 2 months ago

Question
θ\theta is an acute angle. Find the value of θ\theta in degrees.\newlinesec⁡(θ)=2\sec(\theta) = \sqrt{2}\newlineθ=\theta = ____°\degree
Get tutor helpright-arrow

Posted 2 months ago

Question
Evaluate. Write your answer in simplified, rationalized form. Do not round.\newlinecos⁡90∘=\cos 90^\circ = ____
Get tutor helpright-arrow

Posted 3 months ago

View all (130)