$\frac{3}{100} \times \frac{9}{12}$

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Grade 8

Solve multi-step inequalities

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\frac{3}{100} \times \frac{9}{12}

Rewrite the fractions: $\frac{3}{100} \times \frac{9}{12} = \frac{3}{100} \times \frac{3 \times 3}{3 \times 4}$
Multiply the numerators and denominators separately: $= \frac{3 \times 3}{100 \times 4}$
Perform the multiplication: $= \frac{9}{400}$ So, the product of $\frac{3}{100}$ and $\frac{9}{12}$ is $\frac{9}{400}$ .

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3100×912 \frac{3}{100} \times \frac{9}{12} 1003​×129​

$\frac{3}{100} \times \frac{9}{12}$