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Maplewood Furniture Store is having a sale on dining room furniture. When a customer purchases a set of dining chairs, a one-time discount of 5555 $\$ is applied to the total. During the sale, Rhianna buys a set of 66 chairs that match the table she inherited from her grandmother. Rhianna pays 455455 $\$ in all.\newlineWhich equation can you use to find the regular cost, cc, of each chair?\newlineChoices:\newline(A) 6c55=4556c - 55 = 455\newline(B) 55c6=45555c - 6 = 455\newline(C) 6(c55)=4556(c - 55) = 455\newline(D) 55(c6)=45555(c - 6) = 455\newlineWhat is the regular cost of each chair?\newline____ $\$

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Q. Maplewood Furniture Store is having a sale on dining room furniture. When a customer purchases a set of dining chairs, a one-time discount of 5555 $\$ is applied to the total. During the sale, Rhianna buys a set of 66 chairs that match the table she inherited from her grandmother. Rhianna pays 455455 $\$ in all.\newlineWhich equation can you use to find the regular cost, cc, of each chair?\newlineChoices:\newline(A) 6c55=4556c - 55 = 455\newline(B) 55c6=45555c - 6 = 455\newline(C) 6(c55)=4556(c - 55) = 455\newline(D) 55(c6)=45555(c - 6) = 455\newlineWhat is the regular cost of each chair?\newline____ $\$
  1. Understand the problem: Understand the problem.\newlineRhianna buys 66 chairs and gets a one-time discount of $55\$55. She pays a total of $455\$455. We need to find the regular cost of each chair before the discount.
  2. Set up the equation: Set up the equation.\newlineLet cc be the regular cost of each chair. The total cost without the discount would be 66 times the cost of each chair, which is 6c6c. After applying the one-time discount of $55\$55, the total cost is $455\$455. So the equation is 6c55=4556c - 55 = 455.
  3. Identify the equation: Identify the correct equation from the choices.\newlineThe correct equation that represents the situation is (A)6c55=455(A) 6c - 55 = 455.
  4. Solve for c: Solve the equation for c.\newlineAdd 5555 to both sides of the equation to isolate the term with cc on one side:\newline6c55+55=455+556c - 55 + 55 = 455 + 55\newline6c=5106c = 510\newlineNow, divide both sides by 66 to solve for cc:\newline6c6=5106\frac{6c}{6} = \frac{510}{6}\newlinec=85c = 85