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Lucy and her dad went ice-fishing this winter. They caught 88 total fish, including 66 arctic char. If on the last day of the trip, Lucy randomly selected 44 fish to donate to fishermen who hadn't caught any fish that day, what is the probability that all of them are arctic char?\newlineWrite your answer as a decimal rounded to four decimal places.______

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Q. Lucy and her dad went ice-fishing this winter. They caught 88 total fish, including 66 arctic char. If on the last day of the trip, Lucy randomly selected 44 fish to donate to fishermen who hadn't caught any fish that day, what is the probability that all of them are arctic char?\newlineWrite your answer as a decimal rounded to four decimal places.______
  1. Total Fish Count: Total number of fish: 88Arcticchar:$6Arctic char: \$6\)Fish to donate: 44\)Calculate total possible combinations of choosing 44 fish from 88.\(8C44 = \frac{8!8!}{4!(84)!4!(8-4)!}\)
  2. Calculate Total Combinations: 8C4=8!4!4! {}_8C_4 = \frac{8!}{4!4!} =8×7×6×54×3×2×1 = \frac{8 \times 7 \times 6 \times 5}{4 \times 3 \times 2 \times 1} =70 = 70
  3. Calculate Arctic Char Combinations: Calculate combinations of choosing 44 arctic char from 66.
    \substack{6\4}C = \frac{6!}{4!(6-4)!}
  4. Calculate Probability: (64)=6!4!2!\binom{6}{4} = \frac{6!}{4!2!}=6×52×1= \frac{6 \times 5}{2 \times 1}=15= 15
  5. Calculate Probability: 6C4=6!4!2! {}_6C_4 = \frac{6!}{4!2!} =6×52×1 = \frac{6 \times 5}{2 \times 1} =15 = 15 Probability = Favorable outcomes / Total possible outcomes=1570 = \frac{15}{70} =0.2143 = 0.2143 when rounded to four decimal places.

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