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Solve for kk.\newlinelog1019k=19log10k\log_{10}19k = 19\log_{10}k

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Q. Solve for kk.\newlinelog1019k=19log10k\log_{10}19k = 19\log_{10}k
  1. Given Equation Simplification: We are given the equation log1019k=19log10k\log_{10}19k = 19\log_{10}k. We need to find the value of kk that satisfies this equation.\newlineFirst, let's use the power rule of logarithms, which states that logb(mn)=nlogb(m)\log_b(m^n) = n\log_b(m), to simplify the right side of the equation.
  2. Logarithmic Equivalence: Applying the power rule to the right side of the equation, we get:\newlinelog1019k=log10(k19)\log_{10}19k = \log_{10}(k^{19}).\newlineNow, since the bases of the logarithms on both sides of the equation are the same, we can equate the arguments of the logarithms.
  3. Solving for kk: Setting the arguments of the logarithms equal to each other, we have:\newline19k=k1919k = k^{19}.\newlineNow, we need to solve for kk.
  4. Checking Solutions: To solve the equation 19k=k1919k = k^{19}, we can see that k=0k = 0 is not a solution since 19×019\times 0 is not equal to 0190^{19}. We can also see that k=1k = 1 is a solution since 19×119\times 1 is equal to 1191^{19}. Let's check if there are any other solutions.
  5. Final Solution: Dividing both sides of the equation by kk (assuming k0k \neq 0), we get:\newline19=k1819 = k^{18}.\newlineNow, we need to find the value of kk that satisfies this equation.
  6. Final Solution: Dividing both sides of the equation by kk (assuming k0k \neq 0), we get:\newline19=k1819 = k^{18}.\newlineNow, we need to find the value of kk that satisfies this equation.The equation 19=k1819 = k^{18} can only be true if k=1k = 1, because 11 raised to any power is still 11. Any other value of kk raised to the 1818th power will not equal k0k \neq 000.
  7. Final Solution: Dividing both sides of the equation by kk (assuming k0k \neq 0), we get: 19=k1819 = k^{18}. Now, we need to find the value of kk that satisfies this equation.The equation 19=k1819 = k^{18} can only be true if k=1k = 1, because 11 raised to any power is still 11. Any other value of kk raised to the 1818th power will not equal k0k \neq 000.Therefore, the only solution to the equation k0k \neq 011 is k=1k = 1.

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