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log_(7)(7^(9))=x

log⁡7(79)=x \log _{7}\left(7^{9}\right)=x

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Full solution

Q. log⁡7(79)=x \log _{7}\left(7^{9}\right)=x
  1. Identify Base and Argument: Identify the base of the logarithm and the argument.\newlineBase is 77, and the argument is 797^9.
  2. Rewrite Using Logarithm Property: Rewrite the equation using the property of logarithms that log⁡b(bx)=x\log_b(b^x) = x.log⁡7(79)=9\log_{7}(7^9) = 9.
  3. Determine the Exponent: Since the base of the logarithm and the base of the exponent are the same, the answer is the exponent. x=9x = 9.

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