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log_(2)(3x+5)=3

log2(3x+5)=3 \log _{2}(3 x+5)=3

Full solution

Q. log2(3x+5)=3 \log _{2}(3 x+5)=3
  1. Rewrite Logarithmic Equation: Rewrite the logarithmic equation in exponential form: 23=3x+52^3 = 3x + 5.
  2. Calculate Exponential Form: Calculate 232^3: 23=82^3 = 8.
  3. Set Up Equation: Set up the equation: 8=3x+58 = 3x + 5.
  4. Subtract 55: Subtract 55 from both sides: 85=3x8 - 5 = 3x.
  5. Calculate Result: Calculate 85:3=3x8 - 5: 3 = 3x.

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