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Lisa owns a "Random Candy" vending machine, which is a machine that picks a candy out of an assortment in a random fashion. Lisa controls the probability of picking each candy.
The machine is running out of "Honey Bunny," so Lisa wants to program it so that the probability of getting a candy other than "Honey Bunny" twice in a row is greater than 
(9)/(4) times the probability of getting "Honey Bunny" in one try.
Write an inequality that models the situation. Use 
p to represent the probability of getting "Honey Bunny" in one try.

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Lisa owns a

Full solution

Q. Lisa owns a
  1. Define Probability: Let pp be the probability of getting "Honey Bunny" in one try. The probability of not getting "Honey Bunny" in one try is 1p1 - p.
  2. Calculate Probability of Not Getting Twice: To find the probability of not getting "Honey Bunny" twice in a row, we multiply the probability of not getting it in one try by itself: \(1 - p) \times (11 - p) = (11 - p)^22\
  3. Set Up Inequality: Lisa wants this probability to be greater than (94)(\frac{9}{4}) times the probability of getting "Honey Bunny" once, which is (94)×p(\frac{9}{4}) \times p. So, we set up the inequality: (1p)2>(94)×p(1 - p)^2 > (\frac{9}{4}) \times p.

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