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Link 6:52PM Tue Apr 30
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Volume of cubes and rectangular...
Volume of cubes and rectangular...
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Video
Find an equation for a sinusoidal function that has period 
pi, amplitude 1 , and contains the point 
(-(3pi)/(4),4).
Write your answer in the form 
f(x)=Asin(Bx+C)+D, where 
A,B,C, and 
D are real numbers.

f(x)=

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Link 66:5252PM Tue Apr 3030\newlineAA\newlineixl.com\newlinebig lip characters - Google Search\newlineVolume of cubes and rectangular...\newlineVolume of cubes and rectangular...\newlineWrite e\newlineVideo\newlineFind an equation for a sinusoidal function that has period π \pi , amplitude 11 , and contains the point (3π4,4) \left(-\frac{3 \pi}{4}, 4\right) .\newlineWrite your answer in the form f(x)=Asin(Bx+C)+D \mathrm{f}(\mathrm{x})=\mathrm{A} \sin (\mathrm{Bx}+\mathrm{C})+\mathrm{D} , where A,B,C \mathrm{A}, \mathrm{B}, \mathrm{C} , and D \mathrm{D} are real numbers.\newlinef(x)= f(x)= \newline \square \newlineSubmit\newlineWork it out\newlineNot feeling ready yet? These can help:\newlineWrite equations of sine functions from graphs\newlinePractice in the app\newlineSolve absolute value equations

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Q. Link 66:5252PM Tue Apr 3030\newlineAA\newlineixl.com\newlinebig lip characters - Google Search\newlineVolume of cubes and rectangular...\newlineVolume of cubes and rectangular...\newlineWrite e\newlineVideo\newlineFind an equation for a sinusoidal function that has period π \pi , amplitude 11 , and contains the point (3π4,4) \left(-\frac{3 \pi}{4}, 4\right) .\newlineWrite your answer in the form f(x)=Asin(Bx+C)+D \mathrm{f}(\mathrm{x})=\mathrm{A} \sin (\mathrm{Bx}+\mathrm{C})+\mathrm{D} , where A,B,C \mathrm{A}, \mathrm{B}, \mathrm{C} , and D \mathrm{D} are real numbers.\newlinef(x)= f(x)= \newline \square \newlineSubmit\newlineWork it out\newlineNot feeling ready yet? These can help:\newlineWrite equations of sine functions from graphs\newlinePractice in the app\newlineSolve absolute value equations
  1. Calculate Period: The period of a sinusoidal function is given by 2π/B2\pi/B. We are given that the period is π\pi, so we can set B=2π/π=2B = 2\pi/\pi = 2.
  2. Determine Parameters: We have: A=1A = 1 and B=2B = 2. There is no phase shift mentioned, so C=0C = 0 initially. Asin(Bx+C)+DA \sin(Bx + C) + D will become:\newlinef(x)=1sin(2x+0)+Df(x) = 1\sin(2x + 0) + D. Plug point (3π4,4)(-\frac{3\pi}{4}, 4) and solve for DD.\newline4=sin(2(3π4)+0)+D4 = \sin(2(-\frac{3\pi}{4}) + 0) + D \newline4=sin(3π2)+D4 = \sin(-\frac{3\pi}{2}) + D \newline4=1+D4 = -1 + D \newlineB=2B = 200
  3. Find Constant DD: Substituting A=1A = 1, B=2B = 2, C=0C = 0, and D=5D = 5 into the f(x)=Asin(Bx+C)+Df(x) = A\sin(Bx + C) + D gives us the final equation f(x)=sin(2x)+5f(x) = \sin(2x) + 5.

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