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Linear relationship word problems: medium
(4) Google Classroom

0.30 P+0.25 G=57
A homeowner uses 
G hours of natural gas heat and 
P hours of heat from a pellet stove to heat her house one month, with a total of 57 therms of output. How many therms per hour does the pellet stove output?
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Linear relationship word problems: medium\newline(44) Google Classroom\newline0.30P+0.25G=570.30 P+0.25 G=57\newlineA homeowner uses \newlineGG hours of natural gas heat and \newlinePP hours of heat from a pellet stove to heat her house one month, with a total of 5757 therms of output. How many therms per hour does the pellet stove output?\newlineShow calculator\newlineHow do I enter a student-produced response on the SAT? [Show me!]

Full solution

Q. Linear relationship word problems: medium\newline(44) Google Classroom\newline0.30P+0.25G=570.30 P+0.25 G=57\newlineA homeowner uses \newlineGG hours of natural gas heat and \newlinePP hours of heat from a pellet stove to heat her house one month, with a total of 5757 therms of output. How many therms per hour does the pellet stove output?\newlineShow calculator\newlineHow do I enter a student-produced response on the SAT? [Show me!]
  1. Given Equation: We are given the equation 0.30P+0.25G=570.30P + 0.25G = 57, where PP is the number of hours the pellet stove is used and GG is the number of hours the natural gas heat is used. We want to find the therm output per hour of the pellet stove, which is represented by the coefficient of PP in the equation.
  2. Isolate PP: To find the therm output per hour of the pellet stove, we need to isolate PP in the equation. However, since we are not given the value of GG or the total hours used, we cannot solve for PP directly. Instead, we can interpret the coefficient of PP (0.300.30) as the therm output per hour for the pellet stove since it represents the therms produced by one hour of using the pellet stove.
  3. Find Therm Output: Therefore, the therm output per hour of the pellet stove is 0.300.30 therms/hour.

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