Identify limit expression: Identify the limit expression: limx→1−(x2−1)cos(2π∗x).
Notice approaching zero: Notice that as x approaches 1 from the left, x2−1 approaches 0.
Consider cosine function: Consider the exponent cos(2π∗x). When x is close to 1, cos(2π∗x) is close to cos(2π), which is 0.
Indeterminate form: The base (x2−1) is approaching 0, and the exponent is approaching 0. This is an indeterminate form 00.
Apply L'Hôpital's Rule: To resolve the indeterminate form, we can use L'Hôpital's Rule by taking the natural logarithm of the function and then finding the limit.
Apply natural logarithm: Apply the natural logarithm: ln((x2−1)cos(2π∗x))=cos(2π∗x)∗ln(x2−1).
Find limit of product: Now find the limit of cos(2π⋅x)⋅ln(x2−1) as x approaches 1 from the left.
Limit of cosine function: The limit of cos(2π⋅x) as x approaches 1 from the left is 0.
Limit of natural logarithm: The limit of ln(x2−1) as x approaches 1 from the left is ln(0), which is undefined.
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