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lim_(x rarr1^(-))(x^(2)-1)^(cos((pi x)//2))=

limx1(x21)cos((πx)/2)= \lim _{x \rightarrow 1^{-}}\left(x^{2}-1\right)^{\cos ((\pi x) / 2)}=

Full solution

Q. limx1(x21)cos((πx)/2)= \lim _{x \rightarrow 1^{-}}\left(x^{2}-1\right)^{\cos ((\pi x) / 2)}=
  1. Identify limit expression: Identify the limit expression: limx1(x21)cos(πx2)\lim_{x \to 1^{-}}(x^2 - 1)^{\cos(\frac{\pi * x}{2})}.
  2. Notice approaching zero: Notice that as xx approaches 11 from the left, x21x^2 - 1 approaches 00.
  3. Consider cosine function: Consider the exponent cos(πx2)\cos\left(\frac{\pi * x}{2}\right). When xx is close to 11, cos(πx2)\cos\left(\frac{\pi * x}{2}\right) is close to cos(π2)\cos\left(\frac{\pi}{2}\right), which is 00.
  4. Indeterminate form: The base (x21)(x^2 - 1) is approaching 00, and the exponent is approaching 00. This is an indeterminate form 000^0.
  5. Apply L'Hôpital's Rule: To resolve the indeterminate form, we can use L'Hôpital's Rule by taking the natural logarithm of the function and then finding the limit.
  6. Apply natural logarithm: Apply the natural logarithm: ln((x21)cos(πx2))=cos(πx2)ln(x21)\ln((x^2 - 1)^{\cos(\frac{\pi * x}{2})}) = \cos(\frac{\pi * x}{2}) * \ln(x^2 - 1).
  7. Find limit of product: Now find the limit of cos(πx2)ln(x21)\cos\left(\frac{\pi \cdot x}{2}\right) \cdot \ln(x^2 - 1) as xx approaches 11 from the left.
  8. Limit of cosine function: The limit of cos(πx2)\cos\left(\frac{\pi \cdot x}{2}\right) as xx approaches 11 from the left is 00.
  9. Limit of natural logarithm: The limit of ln(x21)\ln(x^2 - 1) as xx approaches 11 from the left is ln(0)\ln(0), which is undefined.

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