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Let 
x=sqrt(7+sqrt(7+sqrt(7+dots)))

Let x=7+7+7+ x=\sqrt{7+\sqrt{7+\sqrt{7+\ldots}}}

Full solution

Q. Let x=7+7+7+ x=\sqrt{7+\sqrt{7+\sqrt{7+\ldots}}}
  1. Assume xx equals expression: Let's assume xx equals the entire expression. So, x=7+7+7+.x = \sqrt{7 + \sqrt{7 + \sqrt{7 + \dots}}}.
  2. Substitute xx in square root: Since the expression inside the square root is the same as xx, we can substitute xx inside the square root. So, we get x=7+xx = \sqrt{7 + x}.
  3. Square both sides: Now, we square both sides to get rid of the square root. This gives us x2=7+xx^2 = 7 + x.
  4. Rearrange to quadratic equation: Rearrange the equation to get a quadratic equation: x2x7=0x^2 - x - 7 = 0.
  5. Solve using quadratic formula: We can solve this quadratic equation using the quadratic formula, x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}, where a=1a = 1, b=1b = -1, and c=7c = -7.
  6. Plug values in formula: Plugging the values into the quadratic formula gives us x=1±1+4×72x = \frac{1 \pm \sqrt{1 + 4 \times 7}}{2}.
  7. Simplify square root: Simplify the expression under the square root: x=1±292x = \frac{1 \pm \sqrt{29}}{2}.
  8. Take positive solution: Since xx is the length and cannot be negative, we take the positive solution: x=1+292x = \frac{1 + \sqrt{29}}{2}.

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