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Let P={3,5,7,9,11}P = \{3, 5, 7, 9, 11\} and Q={2,4,6,8}Q = \{2, 4, 6, 8\}. What is P∩QP \cap Q?\newlineChoices:\newline(A) {2,3,4,6,7,8,9,11}\{2, 3, 4, 6, 7, 8, 9, 11\}\newline(B) ∅\emptyset \newline(C) {2,3,4,5,6,7,8}\{2, 3, 4, 5, 6, 7, 8\}\newline(D) {2,3,4,5,6,7,8,9,11}\{2, 3, 4, 5, 6, 7, 8, 9, 11\}

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Q. Let P={3,5,7,9,11}P = \{3, 5, 7, 9, 11\} and Q={2,4,6,8}Q = \{2, 4, 6, 8\}. What is P∩QP \cap Q?\newlineChoices:\newline(A) {2,3,4,6,7,8,9,11}\{2, 3, 4, 6, 7, 8, 9, 11\}\newline(B) ∅\emptyset \newline(C) {2,3,4,5,6,7,8}\{2, 3, 4, 5, 6, 7, 8\}\newline(D) {2,3,4,5,6,7,8,9,11}\{2, 3, 4, 5, 6, 7, 8, 9, 11\}
  1. Intersection Definition: The intersection of two sets, denoted by P∩QP \cap Q, is the set containing all elements that are both in PP and in QQ.
  2. Set P Elements: We list the elements of set P: {3,5,7,9,11}\{3, 5, 7, 9, 11\}.
  3. Set Q Elements: We list the elements of set Q: {2,4,6,8}\{2, 4, 6, 8\}.
  4. Find Common Elements: We look for common elements between set PP and set QQ.
  5. No Common Elements: There are no common elements between set PP and set QQ, as all elements in PP are odd and all elements in QQ are even.
  6. Intersection Result: Since there are no common elements, the intersection of PP and QQ is the empty set, denoted by ∅\emptyset.

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